Answer:
Pressure = 4.81atm
Explanation:
Pressure = ?
Temperature = 20°C = (20 + 273.15)K = 293.15K
Volume = 2.50L
R = 0.082J/mol.K
n = 0.5mol
From ideal gas equation,
PV = nRT
P = pressure of the ideal gas
V = volume the gas occupies
n = number of moles of the gas
R = ideal gas constant and may varies due to unit of pressure and volume
T = temperature of the ideal gas
PV = nRT
Solve for P,
P = nRT/ V
P = (0.5 * 0.082 * 293.15) / 2.50
P = 12.01915 / 2.50
P = 4.807atm
P = 4.81atm
The pressure of the ideal gas is 4.81atm
The volume that will be occupied at 735 torr and 57 c is 23.12 L
<u><em>calculation</em></u>
- <u><em> </em></u> At STP temperature=273 k and pressure=760 torr
- <u><em> </em></u>by use of combined gas formula
that is P1V1/T1= P2V2/T2
where; P1 =760 torr
T1= 273 K
V1= 18.5 L
P2= 735 torr
T2= 57+273= 330 K
V2=?
- by making V2 the formula of subject
V2= T2P1V1/P2T1
V2= [(18.5L x 330 k x 760 torr)/(735 torr x 273 k)]= 23.12 L
Answer:
Hybridization: sp
Electron geometry: linear
Molecular geometry: linear
Explanation:
H₃CCCH can also be written as its Lewis structure which is shown in the figure attached. The figure shows that the central carbon atom makes a single bond with CH₃ and a triple bond with CH. This means that the hybridization of the carbon is sp and both the electron and molecular geometry are linear with an 180° bond angle.
Answer:
See Explanation Below
Explanation:
A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.
B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5
C) The rate will increase by 4 since you are doubling both you have to multiply them both.
