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Ganezh [65]
3 years ago
5

Find the eighth term of an arithmetic sequence whose fourth term is 19 and whose fifteenth is 52.

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0

Answer:

The correct answer is actually B, 31

Step-by-step explanation:

Here is a link to a video giving an in depth explanation, just delete all of the (space)s

https://( )www.numerade( ).com/questions/find-the-( )indicated-term-( )of-each-sequence-the( )-eighth-term-of-( )the-arithmetic-( )sequence-whose-( )fourth-ter/

Elina [12.6K]3 years ago
3 0

Answer:

its C can u give me brainly

Step-by-step explanation:

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Which of the following statements about UK and UL is true?
dedylja [7]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
16. Solve for "x".<br> a. 6<br> b. 100<br> c. 36
erastovalidia [21]

Answer:

A. 6

Step-by-step explanation:

Using the Pythagorean theorem which states that: <u>Hypotenus² = Opposite² + Adjacent²</u>

Where: hypotenus = 10, opposite = x, adjacent = 8

So:

{10}^{2}  =  {x}^{2}  +  {8}^{2}

Solving for x

100 =  {x}^{2}  + 64

Collect like terms to make x the subject of formula

100 - 64 =  {x}^{2} →36 =  {x}^{2}

36 =  {x}^{2} ⟹ {x}^{2}  = 36

square root both sides of the equation to find the value of x

\sqrt{ {x}^{2} }  =  \sqrt{36} →x = 6

Therefore: Option A is correct

5 0
1 year ago
In a local basketball league championship total 198 games were played, where each team played exactly three games with all the o
kifflom [539]

Answer:

  12

Step-by-step explanation:

When n teams play each other once, the total number of games is n(n-1)/2. Since each team played every other one 3 times, the relationship between number of teams (n) and number of games is ...

  3(n(n-1)/2) = 198

  n(n-1) = 132 = 12·11 . . . . . . multiply by 2/3 and factor

  n = 12 . . . . . . n = -11 is also an extraneous solution to this quadratic equation

12 teams participated in this championship.

6 0
3 years ago
I need help ASAP! I am offering brainiest to whoever answers the question first!!!
lara [203]
-3:1 :) have a nice day!
8 0
3 years ago
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Sergey is solving 5x2 + 20% – 7 = 0. Which steps could he use to solve the quadratic equation by completing the
Mrac [35]

Answer:

5(x^2+4x)=7

5(x^2+4x+4)=7+20

(x+2)=\pm\sqrt{\frac{27}{5}}

Step-by-step explanation:

we have

5x^2+20x-7=0

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

5x^2+20x=7

step 2

Factor 5 left side

5(x^2+4x)=7

step 3

Complete the square

5(x^2+4x+2^2)=7+2^2(5)

5(x^2+4x+4)=7+20

5(x^2+4x+4)=27

step 4

Rewrite as perfect squares

5(x+2)^2=27

step 5

(x+2)^2=\frac{27}{5}

(x+2)=\pm\sqrt{\frac{27}{5}}

(x+2)=\pm\frac{3\sqrt{15}}{5}

step 6

x=-2\pm\frac{3\sqrt{15}}{5}

6 0
3 years ago
Read 2 more answers
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