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diamong [38]
3 years ago
9

Balance the equation KCIO3–> O2+ KCI

Chemistry
2 answers:
Rus_ich [418]3 years ago
7 0

Explanation:

2KCLO3=3O2+2KC

hope this helps

harina [27]3 years ago
3 0

Answer: 2KCIO3–> 3O2+ 2KCI

Explanation:

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If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound
Damm [24]

Answer: The empirical formula for the given compound is NH_3

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen  = \frac{18}{5.8}=3.10\approx 3

For Nitrogen = \frac{5.8}{5.8}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is NH_3

3 0
3 years ago
If 0.500 mol of NaN3 react what mass I'm grams of nitrogen would result
klemol [59]
Looks like 3*.5 mol of N, or 1.5*.5 N2 
<span>convert that to grams.</span>
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Explanation:

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3. Using the solubility of ionic compounds table and/or the solubility rules,
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Nitrogen gas plus hydrogen gas under pressure and at high temperature turns into ammonia. which of the chemical equations matche
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4 years ago
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