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diamong [38]
3 years ago
9

Balance the equation KCIO3–> O2+ KCI

Chemistry
2 answers:
Rus_ich [418]3 years ago
7 0

Explanation:

2KCLO3=3O2+2KC

hope this helps

harina [27]3 years ago
3 0

Answer: 2KCIO3–> 3O2+ 2KCI

Explanation:

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137.33 g/mol

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Methane burns in the presence of oxygen to form carbon dioxide and water.
wlad13 [49]

Answer:

= 9.28 g CO₂

Explanation:

First write a balanced equation:

CH₄ + 2O₂ -> 2H₂O + CO₂

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13.5g O₂ = 0.421875 mol O₂

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Actual ratio is  0.46875 : 0.421875 ≈ 1:1

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So O₂ is the limiting reactant and we use this in our equation

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round to 3 sig figs

= 9.28 g CO₂

5 0
3 years ago
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