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Yuliya22 [10]
4 years ago
11

According to Newton�s first law of motion, if there is no net force (unbalanced forces) acting on an object that is moving at a

constant 30 mph, the object will:
Continue to move at 30 mph

Eventually come to a stop

Change its inertia

Accelerate
Chemistry
1 answer:
Alekssandra [29.7K]4 years ago
7 0

According to Newton’s first law of motion,if there is no net force acting on an object that is moving at a constant 30 mph speed, the object will continue to move at 30 mph.

Option a

<h3><u>Explanation:</u></h3>

"Newton's first law of motion" states that an object at a stationary position or an object moving at a constant velocity continues its state of rest or of motion unless it is acted upon by an "external unbalanced resisting force".

Since the net force acting on this object is zero; the absence of any kind of force (neither internal nor external) is observed and hence the motion at constant 30 mph velocity will continue until it is resisted.

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show by means of a balanced equation how many moles of N2 will be used in reaction to H2 to form 17 moles of NH3
77julia77 [94]
The balanced chemical reaction is:<span>

N2 + 3H2 = 2NH3

<span>We are given the amount of the product to be produced. This will be the starting point of our calculations.

17 mol NH3 ( 1 mol N2 / 2 mol NH3 ) = 8.5 mol N2

Therefore, the required N2 to produce the given amount of ammonia is 8.5 mol.</span></span>
4 0
3 years ago
An element A forms a compound AH3 with hydrogen. Another element B forms a compound BA2 with B. Given that the valency of hydrog
Hatshy [7]

Answer:

A - 3

B - 6

Explanation:

The valency of hydrogen atom is +1

The valancy of an atom of other element combining with the hydrogen atom can be determined from the  number of associated hydrogen.

when H combines with A, three atoms of hydrogen are used. Thus the valency of element A is -3

Now B combines with two molecules of A whose valency is -3

The valency of B would be twice the valency of element A i.e 6

if hydrogen combines with B, then the compound formed will be BH6

8 0
3 years ago
In the reaction Zn + H+ ---&gt; Zn2+ + H2, Zn is oxidized and H is reduced.
Sever21 [200]

Answer:

2H⁺ + 2e → H₂.

Zn → Zn²⁺ + 2e.

Explanation:

  • The reaction includes two half-reactions:

<em>The reduction reaction:</em>

<em>2H⁺ + 2e → H₂.</em>

  • 2.0 moles of hydrogen ions is reduced by 2 electrons to produce 1.0 mole of hydrogen gas.

<em>The oxidation reaction:</em>

<em>Zn → Zn²⁺ + 2e.</em>

  • 1.0 mole of Zn metal is oxidized to Zn²⁺ and releases 2 electrons.

  • <em>The overall reaction will be:</em>

<em>Zn + 2H⁺  → Zn²⁺ + H₂.</em>

7 0
3 years ago
Read 2 more answers
2 A(g) + B(g) ⇄ 2 C(g)
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Answer:

(C) substance B is not involved in the rate-determining step of the mechanism but is involved in subsequent steps.

Explanation:

A. Is incorrect because if the order of the reaction with respect B was one then the rate would increase by the same multiple that B is increased by.

B. If B is reactant then it must be involved in the mechanism of the reaction and in the formation of the product

D. If B was a catalyst then increasing it's amount would affect the rate

E. That is just factually untrue. Effect of reactants on rates can only be found experimentally, not stoichiometrically.

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3 years ago
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Answer:

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