Answer:
Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.
Step-by-step explanation:
Given:
In Δ PQT
PQ = 30 ft
QT = 28 ft
TP = 20 ft
In Δ QRS
QR = 15 ft
RS = 14 ft
SQ = 10 ft
To Prove:
Δ PQT ~ Δ QRS
Proof:
First we consider the ratio of the sides
..............( 1 )
..............( 2 )
..............( 3 )
So By equation ( 1 ), ( 2 ) and ( 3 ) we get
Now in Δ PQT and Δ QRS we have
Which are corresponding sides of a similar triangle in proportion.
∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved
<u>Answer:</u>
An obtuse triangle has two angles 45 and 18. The value of the unknown angle is 
<u>Solution:</u>
Given that two angles of an obtuse triangle is 45 and 18.
Third angle is θ
We are asked to find the value of third unknown angle theta
According to <em>angle sum property of triangle</em>, sum of three angles of triangle is 
This means in our case sum of 45, 18 and θ should be
Hence value of unknown third angle of an obtuse triangle is
Answer:
x=10, y=-3
Step-by-step explanation:
solve by addition/elimination
The best way for him to check his answer would be to simply plug in the value found for x into the equation.
4(2) - 6 = 2
8 - 6 = 2
2 = 2
