This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
Answer:
The most reasonable answer would likely be the first.
"When a pair of parallel lines is intersected by a third line, the alternate exterior angles are congruent."
Step-by-step explanation:
Find the value of r(q(4)), so first you need to find the value of q(4).
q(4), this means that x = 4, so substitute/plug it into the equation to find the value of q(x) when x = 4:
q(x) = -2x - 1 Plug in 4 into "x" since x = 4
q(4) = -2(4) - 1
q(4) = -8 - 1
q(4) = -9
Now that you know the value of q(4), you can find the value of r(x) when x = q(4)
r(x) = 2x² + 1
r(q(4)) = 2(q(4))² + 1 Plug in -9 into "q(4)" since q(4) = -9
r(q(4)) = 2(-9)² + 1
r(q(4)) = 2(81) + 1
r(q(4)) = 163 163 is the value of r(q(4))
Answer:
x≤-3 1/2 or x>1
Step-by-step explanation:
The way we solve this is we simply rearrange the equation using algebra.
Step 1) For the first inequality, subtract 1/2 from both sides. This gets x by itself and turns the RHS into -3 1/2.
Step 2) For the second, add 3 to both sides. Once again, x is by itself, and the RHS is equal to 1.
