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3 years ago

Instructions

Mathematics

1 answer:

qaws [65]3 years ago

3 0

Answer:

part 1 its telling you to measure people

part two is telling you to put it into a graph and find the rate of change. more than likely there won't be a rate of change for you

part three:

y = 0.860x + 3.302

y = 0.860(17) + 3.302

0.860(17) = 14.62

14.62 + 3.302 = 17.922

y = 17.922

sorry this is as far as i had gotten

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Jane had 27 stickers two weeks ago. She bought the same amount of stickers each day for these two weeks. Now she has 237 sticker

lesya [120]

Answer:

Jane bought 15 stickers per day.

Step-by-step explanation:

Given;

Total number of stickers Jane has = 237

Number of stickers 2 weeks ago = 27

To find : Number of stickers she bought each day for two weeks.

Solution,

Let the number of stickers she bought everyday be x.

∴ Number of stickers for 2 weeks = $14\times x=14x$

Now according to question,

Total number of stickers = Number of stickers 2 weeks ago + Number of stickers she bought for 2 weeks

$237=27+14x\\14x=237-27\\14x=210\\x=15$

Thus the number of stickers she bought everyday for 2 weeks is 15.

3 0

3 years ago

Thomas paid $50 for a box of multicolor file folder for his office there were 100 folders in the box what was the cost of each f

Yuliya22 [10]

For the answer to the question above asking what was the cost of each file folder if Thomas paid $50 for a box of the multicolor file folder for his office, there were 100 folders in the box?
this is a grade 2 problem. If you know how to divide you will get the answer.
Just d<span>ivide $50 by 100. Then you'll get the answer. </span>

4 0

4 years ago

What is the answer of 2.365*12.4?

gulaghasi [49]

2.365 * 12. 4 = 29.3260

In mulitplying decimals. Multiply numbers as regular numbers. Ignore the decimals.

From 2.365 * 12.4 make it 2365 *124 = 293260
Then count the total number of decimals of both numbers to put it in the answer.

2.365 has 3 decimals while 12.4 has 1 decimal = 4 decimal places.

Count the decimal places from right to left, arriving to the answer 29.3260

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3 years ago

5m^{2}\sqrt{25m^{8}+15m^{6}+5m^{2}}

xxTIMURxx [149]

You can square the whole problem to cancel out the square root. Might make things easier.

5 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

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4 years ago