Assuming a fair die,
probability of winning 0.25 = (2/6) = 1/3
probability of losing 0.25 = (4/6) = 2/3
Expected win
= sum (proba.*winning)
=0.25*(1/3) + (-0.25)(2/3)
=-0.25/3
= - (1/12) dollars (negative sign means expecting to lose)
5∛(10)∛(x)+4∛(3)<span>∛(x)
But in the comments you wrote the choices and none of them match with the answer i got. so i would say its B</span>
Easy there on the caps, partner.
The nine, using the distributive property, distributes itself across the brackets, and so 9 times t is 9t and 9 times -1 is -9.
Therefore, 9(t-1) = 9t -9
I believe the answer is D b/c each input has one output
