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Marrrta [24]
3 years ago
5

When you double the distance between a pair of charged particles what happens to the force between them?

Physics
1 answer:
Volgvan3 years ago
8 0

Answer:

Force between the two charges becomes one fourth of the initial force.

Explanation:

The electrostatic force acting between any two charges is given as,

F = k\frac{q_{1}q_{2}}{r^{2}}

Here,

F = force

k = Coulomb's constant

q_{1} = magnitude of charge of the first particle

q_{2} = magnitude of charge of the second particle

r = separation between the two charges

From the above relation,

F \propto \frac{1}{r^{2}}

Thus,

\frac{F_{1}}{F_{2}} = \left ( \frac{r_{2}}{r_{1}} \right )^{2}

\frac{F_{1}}{F_{2}} = \left ( \frac{2r}{r} \right )^{2}

\Rightarrow \ F_{2} = \frac{1}{4}F_{4}.

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