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svlad2 [7]
1 year ago
6

If a peregrine falcon dove at its maximum speed for half a mile to catch prey, how many seconds would the dive take? (round your

answer to the nearest second. ) correct answer9
Physics
1 answer:
Natasha2012 [34]1 year ago
7 0

The number of seconds that the dive will take if peregrine falcon dove at its maximum speed for half a mile is 9 seconds.

<h3>How to calculate the time?</h3>

From the complete information, it was stated that the peregrine falcon can reach speed of up to 200 miles per hour.

Therefore, the number of seconds that the dice would take for half a mile will be calculated thus:

1 hour = 200 miles

3600 seconds = 200 miles

1 second will be: = (200/3600) = 0.056 miles

Therefore, the time will be:

200miles / 1 hour = 0.x

x = 0.0025 hours

Therefore, 0.0025 hours will be:

= 0.0025 × 3600

= 9 seconds.

Learn more about time taken on:

brainly.com/question/4931057

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KatRina [158]

Answer:

If she ___(be) rich, she _____ (buy) a new sports car.

Group of answer choices

is/buys

be/buy

were/would buy

were/bought

6 0
2 years ago
Read 2 more answers
Radar uses radio waves of a wavelength of 2.9 m . The time interval for one radiation pulse is 100 times larger than the time of
Mandarinka [93]

Answer:

145 m

Explanation:

Given:

Wavelength (λ) = 2.9 m  

we know,

c = f × λ  

where,

c = speed of light ; 3.0 x 10⁸ m/s

f = frequency  

thus,

f=\frac{c}{\lambda}

substituting the values in the equation we get,

f=\frac{3.0\times 10^8 m/s}{2.9m}

f = 1.03 x 10⁸Hz  

Now,

The time period (T) = \frac{1}{f}

or

T =  \frac{1}{1.03\times 10^8}  = 9.6 x 10⁻⁹ seconds  

thus,

the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s  

Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s  

Now,

For radar to detect the object the pulse must hit the object and come back to the detector.

Hence, the shortest distance will be half the distance travelled by the pulse back and forth.

Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}  

Thus, the minimum distance to target = \frac{290}{2} = 145 m

6 0
2 years ago
object P1 and P2 are in a straight line with the normal to a plane mirror.If P1 and P2 are 18m and 21m away from the mirror. Cal
VARVARA [1.3K]

The distance between object P1 and its image formed is determined as 36 m.

<h3>Distance of the image</h3>

The distance of the image formed by object P1 is calculated as follows;

In a plane mirror; object distance = image distance

image distance of P1 = 18 m

distance between object and image = 18m + 18 m = 36 m

Thus, the distance between object P1 and its image formed is determined as 36 m.

Learn more about plane mirrors here: brainly.com/question/1126858

#SPJ1

8 0
2 years ago
Water flows from a large drainage pipe at a rate of 950 gal/min. What is this volume rate of flow in (a) m3/s , (b) liters/min,
Paladinen [302]

Answer:

0.05997\ m^3/s

3596.1395\ L/min

2.11647\ ft^3/s

Explanation:

1\ gal/min=\dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=0.05997\ m^3/s

Volume rate of flow is 0.05997\ m^3/s

1\ gal/min=3.78541\ L/min\\\Rightarrow 950\ gal/min=950\times 3.78541=3596.1395\ L/min

Volume rate of flow is 3596.1395\ L/min

1\ gal/min=\dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=2.11647\ ft^3/s

Volume rate of flow is 2.11647\ ft^3/s

6 0
3 years ago
Lori’s family is on a road trip. They split their drive into the five legs listed in the table. Find the average velocity for ea
PIT_PIT [208]
Average velocity is displacement  divided by time elapsed; Δv/Δt

You will need to use the information in the table you are given. Subtract: (final velocity - initial velocity) and divide by (final time - initial time).
3 0
3 years ago
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