Hii please help i’ll give brainliest if you give a correct answer please

rosijanka [135]

Answer: The square root of Pi is 1.77245.

Please mark as brainliest

4 0

3 years ago

These are the types of attractions found between molecules. Their strength determines the state of the substance at room tempera

VLD [36.1K]

Answer:

Intermolecular forces

Explanation:

The force of attractions that act between molecules are called intermolecular forces.

Their nature is electromagnetic, this means that they are just an expression of the electromagnetic force.

One example of intermolecular force is the ionic bond: this type of bond occurs when there are two ions, one positively charged and the other one negatively charged, and they are attracted by each other due to the electrostatic force, which therefore creates a bond between them.

Other types of intermolecular forces include:

Hydrogen bond

Ion-dipole forces

Van der Waals forces

The strength of these intermolecular forces determine the state of the substance. In fact, in solids, these forces are very strong, so that the molecules are strongly bond to each other and they cannot move freely, but only vibrate about their fixed position. On the other hand, in gases, these forces are very weak, therefore the molecules are able to move freely away from each other.

5 0

3 years ago

While accelerating at 5.22 m/s/s an object changes its velocity from 6.73 m/s to 29.88 m/s. Over what

yan [13]

Answer:

Explanation:

v² = u² + 2as

s = (v² - u²) / 2a

s = (29.88² - 6.73²) / (2(5.22))

s = 81.1802203065...

s = 81.18 m

4 0

3 years ago

Find the gravitational potential at a point on the earth surface. Take mass as of earth as 5.98×10^24kg,it's radius as6.38×10^6n

andrew-mc [135]

Answer:

$-6.25\cdot 10^7 J$

Explanation:

The gravitational potential at a point on the Earth surface is given by:

$U=-\frac{GM}{R^2}$

where

G=6.67×10^-11Nm^2kg^-2 is the gravitational constant

M=5.98×10^24kg is the Earth's mass

R=6.38×10^6 m is the Earth's radius

Substituting the numbers into the equation, we find

$U=-\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.38\cdot 10^6)}=-6.25\cdot 10^7 J$

5 0

3 years ago

Three identical springs, each with stiffness 1200 N/m are attached in series (that is, end to end) to make a longer spring to ho

OLga [1]

<h2>Answer:</h2>

400N/m

<h2>Explanation:</h2>

When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e

$\frac{1}{m}$ = ∑ⁿ₁ [ $\frac{1}{k_{i}}$ ] -----------------------(i)

That is;

$\frac{1}{m}$ = $\frac{1}{k_{1}}$ + $\frac{1}{k_{2}}$ + $\frac{1}{k_{3}}$ + . . . + $\frac{1}{k_{n}}$ -------------------(ii)

If they have the same value of stiffness say s, then equation (ii) becomes;

$\frac{1}{m}$ = n x $\frac{1}{s}$ -----------------(iii)

Where;

n = number of springs

From the question,

There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;

n = 3

s = 1200N/m

Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;

$\frac{1}{m}$ = 3 x $\frac{1}{1200}$

$\frac{1}{m}$ = $\frac{3}{1200}$

$\frac{1}{m}$ = $\frac{1}{400}$

Cross multiply;

m = 400N/m

Therefore, the stiffness of the longer spring is 400N/m

7 0

4 years ago