Hii please help i’ll give brainliest if you give a correct answer please

A ruler has a division of 1mm. You use the ruler to measure a piece of paper. You find that it is 7.4 cm wide and 8.3 cm long. W

Anastaziya [24]

Answer:

Explanation:

Given the dimension of a paper measured by a ruler as 7.4 cm wide and 8.3 cm long, the area of the paper is expressed using the area for calculating the area of a rectangle as shown;

Area of the piece of paper = Length * Width

Given length = 7.4cm

Length = 74mm (Since 10mm = 1cm)

Width = 8.3cm

Width (in mm) = 83mm

We converted to mm since the ruler used to measure has a division of 1mm.

Substituting the given values into the formula, we will have:

Area of the piece of paper = 74mm * 83mm

Area of the piece of paper = 6,142mm²

Hence, the area of the piece of paper is 6,142mm²

3 0

3 years ago

Types of RM radiation that make up the electromagnetic spectrum are microwaves, infrared light, ultraviolet light, X-rays, and g

HACTEHA [7]

Answer:

True

Explanation:

The electromagnetic spectrum can be regarded as term that give description of range of light that are in existence, and this range from radio waves up to gamma rays. It can be explained as

range of frequencies that electromagnetic radiation takes with thier respective wavelengths as well as photon energies

The Types of electromagnetic radiation that make up the electromagnetic spectrum are

✓ microwaves

✓ infrared light

✓ ultraviolet light

✓X-rays,

✓gamma rays.

4 0

3 years ago

A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m

elena-14-01-66 [18.8K]

Answer:

1,230N

Explanation:

1. Name of the variables:

$f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration$

2. Formulae:

$f=\dfrac{number\text{ }of\text{ }revolutions}{time}$

$\omega=2\pi f$

$a_c=\omega^2 r$

$F_c=m\times a_c$

3. Solution (calculations)

$f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}$

$\omega=2\pi\times0.\overline{60}\approx 3.808rad/s$

$a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2$

$F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N$

3 0

3 years ago

An atom that has a negative four charge will have which of the following? Question 1 options: 4 more protons than electrons An e

Lilit [14]

Electrons: negative charge
Protons: positive charge
Neutrons: negative charge

The atom would have to have more electrons than protons

Hope this helps :)

3 0

2 years ago

You are trying to overhear a juicy conversation, but from your distance of 20.0 m , it sounds like only an average whisper of 30

12345 [234]

Answer:

r₂ = 0.2 m

Explanation:

given,

distance = 20 m

sound of average whisper = 30 dB

distance moved closer = ?

new frequency = 80 dB