Answer:
V = 6.36 m³
Explanation:
For this exercise we will use fluid mechanics relations, starting with the continuity equation.
Let's write the flow equation
Q = v₁ A₁
The area of a circle is
A = π r²
Radius is half the diameter
A = π/4 d²
Q = v₁ π/4 d₁²
Q = π/ 4 15 0.03 2
Q = 0.0106 m3 / s
The volume of water in t = 10 min = 10 60 = 600 s
Q = V / t
V = Q t
V = 0.0106 600
V = 6.36 m³
Answer:
It can be calculated from Snell's law by setting the refraction angle i.e. equal to 90°.
Hope it helps!
The correct answer would be C. Unaware because it is the opposite of leery
Answer:
The ball is making a circular motion. The centripetal acceleration in a circular motion is
~
Explanation:
Normally in physics questions like this, we use all the information in the question. Here, we left out the mass or the height of the object. I assume there is more sub-questions that is not shared here. However, the centripetal acceleration can be found by using the velocity and the radius only.
The mass of the object doesn't matter. The change in its momentum is equal to the impulse that changed it ... 15 N-sec.
