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3 years ago

How does the input distance of a single fixed pulley compare to the out- put distance?

1 answer:

4 0

A pulley is another sort of basic machine in the lever family. We may have utilized a pulley to lift things, for example, a banner on a flagpole.

<u>Explanation:</u>

The point in a fixed pulley resembles the support of a lever. The remainder of the pulley behaves like the fixed arm of a first-class lever, since it rotates around a point. The distance from the fulcrum is the equivalent on the two sides of a fixed pulley. A fixed pulley has a mechanical advantage of one. Hence, a fixed pulley doesn't increase the force.

It essentially alters the direction of the force. A moveable pulley or a mix of pulleys can deliver a mechanical advantage of more than one. Moveable pulleys are appended to the item being moved. Fixed and moveable pulleys can be consolidated into a solitary unit to create a greater mechanical advantage.

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The manometer shown in fig. 2 contains water and kerosene. with both tubes open to the atmosphere, the free-surface elevations d

ozzi

The solution for this problem is: In the figure, you now know that total length of the kerosene column
So at x – xPatm + Pkg(H0 th) = Pa + Pwgh
Now H0 + h = 20 + 91.1 mm = 111.1 mm
Therefore = Pkg 0.1111 – P2g= h = 56 x 0.111 – 98 / 1000 x 9.81= 0.081 m or 81 mn
Therefore H0 = 111.1 - 81= 30.1 mm

6 0

3 years ago

On planet X, an object weighs 7.04 N. Onplanet B where the magnitude of the free-fallacceleration is 1.91g(whereg= 9.8 m/s2isthe

timurjin [86]

<h2>Mass of object in Earth is 1.37 kg</h2>

Explanation:

On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.

We have

Weight = Mass x Acceleration due to gravity

On planet B

25.74 = Mass x 1.91 g

25.74 = Mass x 1.91 x 9.81

Mass = 1.37 kg

Mass is constant for an object. It will not change with location.

Mass of object in Earth = Mass of object in Planet B

Mass of object in Earth = 1.37 kg

4 0

3 years ago

Contrast the force of gravity between these pairs of objects a 1 kg mass and a 2 kg mass that are 1 m apart and two 2 kg masses

Yuki888 [10]

Solution

Force between pair of objects of masses 1kg and 2kg that are 1m apart is given as

$F=G\times \frac{1\times 2}{1^2}$

here G is gravitational constant

G= $6.674\times10^{-11}Nm^2kg^{-2}$

therefore,

$F=6.674\times10^{-11}Nm^2kg^{-2}\times 2$

$F=13.348\times10^{-11}Nm^2kg^{-2}$

similarly Force between pair of objects of masses 2kg each that are 1m apart is given as

$F'=G\times \frac{2\times 2}{1^2}$

$F'=6.674\times10^{-11}Nm^2kg^{-2}\times 4$

$F'=2\times 13.348\times10^{-11}Nm^2kg^{-2}$

or F'=2F

it means Force between pair of objects of masses 2kg each that are 1m apart is equal to twice the Force between pair of objects of masses 1kg and 2kg that are 1m

7 0

3 years ago

Why there is tides in sea and ocean

AleksandrR [38]

Answer:

<em> Tides are the rise and fall of sea levels. Tides occur due to the gravitational forces exerted on the Earth by moon, and to a lesser extent, the sun. That's why tides occur in ocean or sea.</em>

Hope this helps

7 0

4 years ago

Which event took place during the Copernican revolution, when most people started to believe in a heliocentric model of the sola

dem82 [27]

Answer:

Explanation:

Just cuz.... b

7 0

3 years ago

Read 2 more answers