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Alexeev081 [22]
3 years ago
7

A transformer connected to a 120-V (rms) ac line is to supply 13,000 V (rms) for a neon sign. To reduce shock hazard, a fuse is

to be inserted in the primary circuit; the fuse is to blow when the rms current in the secondary circuit exceeds 8.50 mA. What current rating should the fuse in the primary circuit have?
Physics
1 answer:
never [62]3 years ago
8 0

Answer:

The current is 0.921 A.

Explanation:

Given that,

Voltage = 120 V

Current = 13000

Current exceeds = 8.50 mA

We need to calculate the current rating

Using relation of current and voltage

\dfrac{I_{p}}{I_{s}}=\dfrac{V_{s}}{V_{p}}

I_{s}=\dfrac{I_{p}\timesV_{p}}{V_{s}}.....(I)

Where, I_{s} = current in primary circuit

I_{s} = current in secondary circuit

V_{s} = voltage in primary circuit

V_{s} = voltage in primary circuit

Put the value into the formula

I_{s}=\dfrac{13000\times8.50\times10^{-3}}{120}

I_{s}=0.921\ A

Hence, The current is 0.921 A.

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