All categories

2 years ago

I need helppp on my test and i can't get it wrongggg

Mathematics

1 answer:

Artyom0805 [142]2 years ago

6 0

Answer:

Perimeter = 16x + 16

Area = 40x + 15

Step-by-step explanation:

Perimeter = the sum of all the side lengths

Perimeter = 2(8x+3) + 2(5) = 16x + 6 + 10 = 16x + 16

Area = product of base times height

Area = (8x+3)*5 = 40x + 15

You might be interested in

Turn 32/64 into a percent?

alexandr402 [8]

To turn 32/64 into a percent, you have to divide the numerator by the denominator and then multiply the answer by 100.

So, for this question, divide 32 by 64 which is 0.50. Multiply this decimal by 100 and you get 50.

So 50% is the percent for 32/64.

Hope it helps :)

5 0

3 years ago

Read 2 more answers

A school wishes to enclose its rectangular playground using 480 meters of fencing.

Harlamova29_29 [7]

Answer:

Part a) $A(x)=(-x^2+240x)\ m^2$

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

$P=2(L+W)$

we have

$P=480\ m\\L=x\ m$

substitute

$480=2(x+W)$

solve for W

$240=x+W\\W=(240-x)\ m$

Find the area of the rectangular playground

The area is given by

$A=LW$

we have

$L=x\ m\\W=(240-x)\ m$

substitute

$A=x(240-x)\\A=-x^2+240x$

Convert to function notation

$A(x)=(-x^2+240x)\ m^2$

Part b) What side length x gives the maximum area that the playground can have?

we have

$A(x)=-x^2+240x$

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

$A(x)=-x^2+240x$

Factor -1

$A(x)=-(x^2-240x)$

Complete the square

$A(x)=-(x^2-240x+120^2)+120^2$

$A(x)=-(x^2-240x+14,400)+14,400$

$A(x)=-(x-120)^2+14,400$

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

$x=120\ m$

$W=(240-120)=120\ m$

The playground is a square

$A=120^2=14,400\ m^2$

8 0

3 years ago

Slope of -1,0 and 10,18

steposvetlana [31]

You should find the slope using (y2 - y1) / (x2 - x1) = m

m = (18 - 0) / (10 - (-1))

m= 18 / 11

Therefore the slope is 18/11

6 0

3 years ago

Read 2 more answers

Identify the coordinates for point D

Radda [10]

Answer:

Your Picture is just of -3????

Step-by-step explanation:

5 0

3 years ago

Order from least to greatest .square root of 2 .pi .4.5

valkas [14]

The way you have it is correct because root 2 is roughly 1.4 pi approximately is 3.4 and 4.5 is a rational number

8 0

2 years ago