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dezoksy [38]
3 years ago
13

Solve the system by substitution.

Mathematics
1 answer:
Brut [27]3 years ago
3 0

Answer:

((1)/(2),-(1)/(2))

Step-by-step explanation:

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A rectangular region is removed from another rectangular region to create the shaded region shown below. Find the area of the sh
Simora [160]

Answer:

wgtvwthrr

Step-by-step explanation:

3 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
ich sequence of transformations would result in a figure that is similar, but not congruent, to the original figure? Select all
n200080 [17]
Translations, reflections, and rotations always result in a figure that is congruent. Only dilations with a scale factor other than 1 will give a similar, but not congruent, figure.

The 1st and 4th selections apply.
6 0
3 years ago
f(x) = −16x2 + 24x + 16 Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points) WILL GIVE BRAINLIEST
castortr0y [4]

Answer:

Step-by-step explanation:

f(x) = −16x2 + 24x + 16 = 0 can be reduced to -2x^2 + 3x + 2 = 0 and then to 2x^2 - 3x - 2 = 0.  Solve this for x using the quadratic formula:

The discriminant is b^2 - 4ac = (-3)^2 - 4(2)(-2) = 9 + 16 = 25.

Therefore the roots are:

     -(-3) ± √25        3 ± 5

x = ----------------- = ------------  =>  x = 2 and x = -1/2

           2(2)                  4

The x-intercepts are points:  (2, 0) and (-1/2, 0)

Because the coefficient of the x^2 term is negative, this graph opens down and the vertex represents a maximum.

To graph this function, find and plot the vertex.  It is exactly halfway between the x-intercepts, that is, at x = 1 1/4, for which the y value is 21:

vertex and maximum at (5/4, 21)

Finally, find the y-intercept.  Let x = 0; we find that y = 16.  The y-intercept is 0, 16)

We now have four points on the graph and know where the maximum is.  Plot this max (5/4, 21) and the x-intercepts (2, 0) and (-1/2, 0), and finally the y-intercept.  Draw a smooth curve through these points, remembering that the graph is symmetrical about the axis of symmetry x = 5/4.

3 0
3 years ago
Amanda worked the entire summer before her freshman year of college. She saved $2000. She withdraws $150 per week for expenses.
ivolga24 [154]

Answer:

12 weeks.

Step-by-step explanation:

Amanda starts with $2000 and is getting $150 per week which means that we can make the expression:

2000-150n=200

The expression is equal to 200 because is the limit where we can arrive to avoid the fee, then the n is the number of weeks that we are looking for:

150n=2000-200\\n=\frac{1800}{200}\\n=12

n=12 weeks

3 0
3 years ago
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