Question

2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

Answer 1

Answer:

a) $\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}$

$\text{no of moles of sucrose}=\frac{1.202g}{342g/mol}=0.0035moles$

b) Moles of carbon in 1 mole of sucrose $C_{12}H_{22}O_{11}$= 12 moles

Moles of carbon in  0.0035 moles of sucrose $C_{12}H_{22}O_{11}=\frac{12}{1}\times 0.0035=0.042moles$

Moles of hydrogen in 1 mole of sucrose $C_{12}H_{22}O_{11}$= 22 moles

Moles of hydrogen in  0.0035 moles of sucrose $C_{12}H_{22}O_{11}=\frac{22}{1}\times 0.0035=0.077moles$

Moles of oxygen in 1 mole of sucrose $C_12H_22O_11$= 11 moles

Moles of oxygen in  0.0035 moles of sucrose $C_{12}H_{22}O_{11}=\frac{11}{1}\times 0.0035=0.042moles$

c)  1 mole of carbon contains $=6.023\times 10^{23}atoms$

0.042 moles of carbon contain $=\frac{6.023\times 10^{23}}{1}\times 0.042=0.25\times 10^{23}atoms$

1 mole of hydrogen contains $=6.023\times 10^{23}atoms$

0.077 moles of hydrogen contain $=\frac{6.023\times 10^{23}}{1}\times 0.077=0.46\times 10^{23}atoms$

1 mole of oxygen contains $=6.023\times 10^{23}atoms$

0.042 moles of oxygen contain $=\frac{6.023\times 10^{23}}{1}\times 0.042=0.25\times 10^{23}atoms$