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3 years ago

2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

Chemistry

1 answer:

nexus9112 [7]3 years ago

7 0

Answer:

a) $\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}$

$\text{no of moles of sucrose}=\frac{1.202g}{342g/mol}=0.0035moles$

b) Moles of carbon in 1 mole of sucrose $C_{12}H_{22}O_{11}$ = 12 moles

Moles of carbon in 0.0035 moles of sucrose $C_{12}H_{22}O_{11}=\frac{12}{1}\times 0.0035=0.042moles$

Moles of hydrogen in 1 mole of sucrose $C_{12}H_{22}O_{11}$ = 22 moles

Moles of hydrogen in 0.0035 moles of sucrose $C_{12}H_{22}O_{11}=\frac{22}{1}\times 0.0035=0.077moles$

Moles of oxygen in 1 mole of sucrose $C_12H_22O_11$ = 11 moles

Moles of oxygen in 0.0035 moles of sucrose $C_{12}H_{22}O_{11}=\frac{11}{1}\times 0.0035=0.042moles$

c) 1 mole of carbon contains $=6.023\times 10^{23}atoms$

0.042 moles of carbon contain $=\frac{6.023\times 10^{23}}{1}\times 0.042=0.25\times 10^{23}atoms$

1 mole of hydrogen contains $=6.023\times 10^{23}atoms$

0.077 moles of hydrogen contain $=\frac{6.023\times 10^{23}}{1}\times 0.077=0.46\times 10^{23}atoms$

1 mole of oxygen contains $=6.023\times 10^{23}atoms$

0.042 moles of oxygen contain $=\frac{6.023\times 10^{23}}{1}\times 0.042=0.25\times 10^{23}atoms$

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3 years ago

Read 2 more answers

Please help, its urgent.

san4es73 [151]

Answer:

Mass of excess reactant left = 179.6 g

Limiting reactant = nitrogen

Mass of ammonia formed = 200.6 g

Explanation:

Given data:

Mass of nitrogen = 165.0 g

Mass of hydrogen = 215.0 g

Limiting reactant = ?

Mass of ammonia formed = ?

Mass of excess reactant left = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 165.0 g/ 28 g/mol

Number of moles = 5.9 mol

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 215.0 g/ 2 g/mol

Number of moles = 107.5 mol

Now we will compare the moles of ammonia with both reactant.

H₂ : NH₃

3 : 2

107.5 : 2/3×107.5 = 71.7 mol

N₂ : NH₃

1 : 2

5.9 : 2/1×5.9 = 11.8 mol

Less number of moles of ammonia are formed by the nitrogen it will act as limiting reactant.

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 11.8 mol × 17 g/mol

Mass = 200.6 g

Mass of hydrogen left:

We will compare the moles of hydrogen and nitrogen.

N₂ : H₂

1 : 3

5.9 : 3/1×5.9 = 17.7 mol

Out of 107.5 moles 17.7 moles of hydrogen react with nitrogen.

Number of moles left unreacted = 107.5 - 17.7 mol = 89.8 mol

Mass of hydrogen left:

Mass = number of moles × molar mass

Mass = 89.8 mol × 2 g/mol

Mass = 179.6 g

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3 years ago

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch

matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.

Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

Hydrochloric acid, $HCl$

On adding $HCl$ (strong acid) in water, it will completely dissociates into ions ( $H^{+}$ and $Cl^{-}$ ) and thus, it is a strong electrolyte.

Sodium hydroxide, $NaOH$

On adding $NaOH$ (strong base) in water, it will completely dissociates into ions ( $Na^{+}$ and $OH^{-}$ ) and thus, it is a strong electrolyte.

Formic acid, $HCOOH$

On adding $HCOOH$ (weak acid) in water, it will partially dissociates into ions ( $H^{+}$ and $HCOO^{-}$ ) and thus, it is a weak electrolyte.

Methyl amine, $CH_3NH_2$

On adding $CH_3NH_2$ (weak base) in water, it will partially dissociates into ions ( $CH_3NH_3^{+}$ and $OH^{-}$ ) and thus, it is a weak electrolyte.

Potassium chloride, $KCl$

On adding $KCl$ in water, it will completely dissociates into ions ( $K^{+}$ and $Cl^{-}$ ) and thus, it is a strong electrolyte.

Ethanol, $C_2H_5OH$

On adding $C_2H_5OH$ in water, it will not dissociates into ions and thus, it is a nonelectrolyte.

Sucrose, $C_{12}H_{22}O_{11}$

On adding $C_{12}H_{22}O_{11}$ in water, it will not dissociates into ions and thus, it is a nonelectrolyte.

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3 years ago

For each of the following, indicate if the number of half-lives elapsed is:

Hunter-Best [27]

Answer:

a. one half-life

b. three half-lives

c. two half-lives

Explanation:

The number of half-lives elapsed, n, is calculated dividing the time by the half-life time:

n = time / half-life time

a. A sample of Ce-141 with a half-life of 32.5 days after 32.5 days

n = 32.5 days / 32.5 days = 1 half-life

b. A sample of F-18 with a half-life of 110 min after 330 min

n = 330 min / 110 min = 3 half-lives

c. A sample of Au-198 with a half-life of 2.7 days after 5.4 days

n = 5.4 days / 2.7 days = 2 half-lives

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3 years ago