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Juliette [100K]
3 years ago
6

Which is the solution of the equation y=4x+3

Mathematics
2 answers:
NemiM [27]3 years ago
3 0

Answer:

It is not possible to solve the equation y = 4x + 3. This is merely a relation between two variables x and y. The variable y is 3 greater than 4 times the variable x.

Step-by-step explanation:

What book?

kobusy [5.1K]3 years ago
3 0
I have no clue hahahaha
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Is (4, -2) a solution of the inequality? Why or why not?
Leona [35]

Answer:

No

Step-by-step explanation:

The point is not in the shaded section. Every single point on the shaded section is a solution.

8 0
3 years ago
Smplify the following algebraic expression: 6(2y + 8) - 2(3y - 2)
ra1l [238]

Answer:

6y +52

Step-by-step explanation:

6(2y + 8) - 2(3y - 2)

Distribute

12y + 48 - 6y +4

Combine like terms

6y +52

5 0
4 years ago
In the algebraic expression 7 divided by y ... what is the coefficient of y
Tatiana [17]
Since there isn't a number before the y, we assume the coefficient is just 1. I hope this helps
4 0
4 years ago
QUICK whoever gives right answer gets brainly
velikii [3]

Answer:

the number of hours worked

Step-by-step explanation:

6 0
3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. Wellpoint provides a v
Veronika [31]

Answer:

The 95% confidence interval for the mean savings is ($60.54, $81.46).

Step-by-step explanation:

As there is no information about the population standard deviation of savings and the sample is not large, i.e. <em>n</em> = 20 < 30, we will use a <em>t</em>-confidence interval.

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}

For the data provided compute the sample mean and standard deviation as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{ X_{i}}=\frac{1}{20}\times [92+34+40+...+53+82]=71

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 9492 }{ 20 - 1} } \approx 22.35

The critical value of <em>t</em> for <em>α</em> = 0.05 and (n - 1) = 19 degrees of freedom is:

t_{\alpha/2, (n-1)}=t_{0.025, 19}=2.093

*Use a <em>t</em>-table for the value.

Compute the 95% confidence interval for the mean savings as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}\\=71\pm 2.093\times\frac{22.35}{\sqrt{20}}\\=71\pm 10.46\\=(60.54, 81.46)

Thus, the 95% confidence interval for the mean savings is ($60.54, $81.46).

3 0
3 years ago
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