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Tresset [83]
4 years ago
13

Captain Liz is going to load her cruise ship with bags of sugar. She has room for 19 bags of sugar. She has allotted for 121 pou

nds of sugar on her ship. She can choose from 7-pound bags (the variable s) or 10-pound bags (the variable p). Which equations would be a constraint to Captain Liz maximizing her sugar load?
Mathematics
1 answer:
Bad White [126]4 years ago
7 0
: 1) If you were going to solve these, you would set them up like this. s+p=19 7s+10p=121 among the choices, b is the only one that is equivalent to one of these equations 2) The problem looks a little confusing. If the price is per box then they easily make $275. 8b+9h=53 20*8b+30*9h=275 If it's per batch, the answer is B. 3. x^2+y^2=16 y=x+4 solve the first equation for y y=√16-x^2 x+4=√16-x^2 (x+4)^2=16-x^2 x^2+8x+16=16-x^2 2x^2+8x=0 2x(x+4)=0 x=0 or x=-4 (be carefull i copyed and pasted the answer)
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How many whole numbers are from 33 to 76?
VARVARA [1.3K]
Answer:
43

Step by step Explanation:
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5 0
3 years ago
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A 15 foot pole is leaning against a tree. The bottom of the pole is 8 feet away from the bottom of the tree. Approximately how h
mrs_skeptik [129]

Answer:

The top of the pole is approximately <u>13 feet</u> high up the tree.

Step-by-step explanation:

The diagram for the given scenario is shown below.

From triangle ABC, A is the top of pole and B is the bottom of pole.

AC is the height of tree. BC is the distance of the  bottom of pole from the tree.

Given:

AB = 15 ft, BC = 8 ft

To find:

AC = ?

Since triangle ABC is right angled triangle, we apply Pythagoras Theorem to find the unknown side. So,

AC^2+BC^2=AB^2\\\\AC^2+8^2=15^2\\\\AC^2+64=225\\\\AC^2=225-64\\\\AC^2=161\\\\AC=\sqrt{161}=12.7\approx 13\ ft

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7 0
4 years ago
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0.2) Sharad bought one quintal of onions for Rs 2000. Later he
dalvyx [7]

Answer: Loss, 200 Rs

Step-by-step explanation:

Given

Sharad bought  a quintal of onion i.e. 1000\ kg for Rs.\ 2000

So, the cost price of onion is

\Rightarrow \dfrac{2000}{100}=20\ \text{Rs per kg}

He sells it at 18\ \text{Rs. per kg}

Here, the Selling price is less than the cost price

So, he incurs a loss of 2\ \text{Rs per kg}

For a quintal it is

\Rightarrow 2\times 100=200\ \text{Rs}

\Rightarrow \text{Loss }\ \%=\dfrac{C.P.-S.P.}{C.P.}\times 100\\\\\Rightarrow \text{Loss }\ \%=\dfrac{20-18}{20}\times 100=10\%

6 0
3 years ago
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