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3 years ago

Give an example of a diatomic molecule found in Earth's atmosphere.

Chemistry

1 answer:

ANTONII [103]3 years ago

8 0

Answer:

oxygen is an example of a diatomic molecule found in earth's atmosphere!

Explanation:

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A welding torch produces a flame by burning acetylene fuel in the presence of oxygen the energy released from the acetylene fuel

Volgvan

Answer : Chemical energy to thermal energy

Explanation : When the welding torch uses the acetylene fuel for producing flame it is using the chemical acetylene to generate energy in form of light, after the flame is produced the fuel is used for melting a metal which is utilizing the thermal energy. So the ultimate final product is generated from chemical to thermal and so the energy transformation is from chemical energy to thermal energy.

8 0

3 years ago

Read 2 more answers

the empirical formula for a compound used as a green paint pigment is C2H3As3Cu2O8. The molar mass of its molecular formula was

melisa1 [442]

Answer:

Molecular formula = C₄H₆As₆Cu₄O₁₆

Explanation:

Given data:

Empirical formula = C₂H₃As₃Cu₂O₈

Molar mass of compound = 1013 g/mol

Molecular formula = ?

Solution:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass of C₂H₃As₃Cu₂O₈ is 506.897 g/mol

by putting values.

n = 1013 / 506.897

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₂H₃As₃Cu₂O₈)

Molecular formula = C₄H₆As₆Cu₄O₁₆

3 0

3 years ago

How many grams of butane were in 1. 000 atm of gas at room temperature?

dimaraw [331]

The mass in grams of butane at standard room temperature is 53.21 grams.

<h3>How can we determine the mass of an organic substance at room temperature?</h3>

The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:

PV = nRT

Pressure = 1.00 atm
Volume = 22.4 L
Rate = 0.0821 atm*L/mol*K
Temperature = 25° C = 298 k

1 × 22.4 L = n × (0.0821 atm*L/mol*K× 298 K)

n = 22.4/24.4658 moles

n = 0.91556 moles

Recall that:

number of moles = mass(in grams)/molar mass

mass of butane = 0.91556 moles × 58.12 g/mole

mass of butane = 53.21 grams

Learn more about calculating the mass of an organic substance here:

brainly.com/question/14686462

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3 0

2 years ago

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0

3 years ago

How many atoms are in 1.50 moles of fluorine gas

evablogger [386]

1.8x10^24 atoms is How many atoms are in 1.50 moles of fluorine gas

8 0

3 years ago