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LiRa [457]
3 years ago
13

Physostigmine, an alkaloid obtained from a West African plant (Physotigma venenosum),is used in the treatment of glaucoma. Treat

ment of physostigmine with methyl iodide gives a quaternary ammonium salt. What is the structure of this salt?

Chemistry
1 answer:
ozzi3 years ago
8 0

Answer:

The structure of the salt is attached.

Explanation:

Physostigmine, an alkaloid obtained from a West African plant (Physotigma venenosum),is used in the treatment of glaucoma. Treatment of physostigmine with methyl iodide gives a quaternary ammonium salt. What is the structure of this salt?

The structure of the salt is attached

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The ion formed by an atom of sulfur when it gains two electrons is called a:
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Answer:

sulfide ion

Explanation:

however, when non-metalic elements gain electrons to form anions the end of their name is change to "-ide".foe example, a flourin atom gains one electronto become a flouride ion(F`) and sulfur gains two electrons to become a sulfide ion(s^2)

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3 years ago
What is the affect of attraction or pull gravity between the sun and moon
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The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8 cm

for a BCC structure, the atomic radius is equal to

r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3}  }{4}=2.3103x10^{-8}cm

7 0
3 years ago
Does Krypton become a plasma
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Answer:

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Explanation:

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8 0
3 years ago
There are 4.78 g of dry LICIO4 and
astraxan [27]

Answer:

The number of moles of H₂O is 0.135 mol.

The number of moles of LiClO₄ is 0.0449 mol.

Explanation:

Mole is an important standard unit used for the measurement of large quantities of atoms, molecules, or other particles. One mole is equal to 6.022×10²³ units.

The number of moles of a substance is calculated by:

\frac{mass of substance}{molecular weight of  substance}

To find the number of moles of H₂O:

Mass of H₂O in the sample = 2.43g

The molecular weight of H₂O = 18.02g

Number of moles = \frac{2.43}{18.02} = 0.135 mol.

To find the number of moles of LiClO₄:

Mass of LiClO₄ given = 4.78g

The molecular weight of LiClO₄ = 106.39g

Number of moles = \frac{4.78}{106.39} = 0.0449 mol.

Learn more about Moles here:

brainly.com/question/855186

#SPJ2

4 0
2 years ago
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