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Sedbober [7]
3 years ago
8

While examining the color of an engine's coolant: Technician A says that because it is orange, the cooling system should be flus

hed and new coolant put into the system. Technician B says that if the coolant looks rusty, the cooling system should be flushed and new coolant put into the system. Who is correct?
Engineering
1 answer:
Stells [14]3 years ago
4 0

Answer:

Technician B is correct.

Explanation:

In every vehicles, coolants are very important as it keeps the engine cool and keep it running. The coolant serves the purpose of dissipating away the heat that is generated when the engine runs.

When the engine runs, the coolant passes all over the heating surfaces in the engine thus carrying away the heat along with it. With time the color of the coolant changes to rusty brown color when the coolant serves its purpose . It also washes away all the dirt particles from the engine part along with it. Thus the color changes and it is now can be flushed from the engine sump and fresh coolant can be put in to the engine.

Thus in the context, technician B is correct.

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The hull of a vessel develops a leak and takes on water at a rate of 57.5 gal/min. When the leak is discovered the lower deck is
leva [86]

Answer:

It will be around 146,27 min since the pump is turned on until the deck is clear of the water.

Explanation:

When the leak is discovered and the pump is turned on, the lower deck is already submerged and the leak is not fixed; then, in order to have the deck clear of water, the bilge pump has to remove the <em>accumulated water </em>(V_{0}) and the <em>water that is taking on</em> (r_{in}*t) through the leak. We can represent this mathematically as follow:

V_{0} +r_{in} *t-r_{out}*t=0  <em>Equation 1</em>

Where:

V_{0}: is the accumulated water when the leak was discovered

r_{in}: is the takes on rate through the leak = 57.5 gal/min

r_{out}: is the removing rate of the bilge pump = 73.8 gal/min

t= is the time since the pump is turned on until the deck is clear of water.

To calculate the accumulated water (V_{0}), we will model the lower deck as a flat-bottomed container with a bottom surface area of 510 ft^{2} and straight vertical sides. Knowing that the level submerged is 7.5 inches, and performing the corresponding unit conversions, we obtain:

V_{0}= bottom surface area * lever submerged

V_{0}= 510ft^{2}*7.5 in*\frac{1ft}{12in}=318.75 ft^{3}*7.48\frac{gal}{1ft^{3}}=2384.25 gal <em>Equation 2</em>

Solving equation 1 for time (t), and replacing the value obtained in equation 2, we get:

t=\frac{V_{0}}{(r_{out}-r_{in})} =\frac{2384.25 gal}{(73.8-57.5)gal/min}=146,27 min

8 0
3 years ago
19/32 reduced to its lowest form
d1i1m1o1n [39]

Answer:

19/32

Explanation:

19/32 is already in its lowest form

8 0
3 years ago
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7 0
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A resistance of 30 ohms is placed in a circuit with a 90 volt battery. What current flows in the circuit?
blagie [28]

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3A

Explanation:

Using Ohms law U=I×R solve for I by I=U/R

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