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prohojiy [21]
3 years ago
8

A roller-coaster car is traveling at a speed of 23 m/s when it passes through point B. At that point, it enters a concave down c

ircular section of the track that has a radius of curvature of 60 m. After it reaches point B, the car’s speed increases at a rate of 4.75 m/s2. Determine the time it takes for the car to reach point D.

Engineering
1 answer:
ycow [4]3 years ago
8 0

Answer:

See it in the pic

Explanation:

See it in the pic

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Inspections may be_____ or limited to a specific area such as electrical or plumbing
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A is the answer for the sentence
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Think of the differences between circuit-switching and packet-switching paradigms in the Internet core design. Assume an Interne
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Answer:

0.264 ; 0.079

Explanation:

Given that:

Sample size, n = 100

Probability of being active, p = 1% = 1/100 = 0.01

Using the binomial probability relation :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

Probability that more than 1 user will be active

P(x > 1) = 1 - [p(x=0) + p(x = 1)]

P(x = 0) = 100C0 * 0.01^0 * 0.99^100 = 0.366

P(x = 1) = 100C1 * 0.01^1 * 0.99^99 = 0.370

P(x > 1) = 1 - [0.366 + 0.370]

P(x > 1) = 0.264

2.)

Probability that more than 2 user will be active

P(x > 2) = 1 - [p(x=0) + p(x = 1) + p(x = 2)]

P(x = 0) = 100C0 * 0.01^0 * 0.99^100 = 0.366

P(x = 1) = 100C1 * 0.01^1 * 0.99^99 = 0.370

P(x = 2) = 100C2 * 0.01^2 * 0.99^98 = 0.185

P(x > 1) = 1 - [0.366 + 0.370 + 0.185]

P(x > 1) = 0.079

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Example for strengthening mechanism in single-phase material A. Dispersion strengthening B. Precipitation hardening C. Fiber str
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Example for strengthening mechanism in single-phase material: Strain hardening- D.

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Answer:

Hi there...

Explanation:

Please give me brainliest :)

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A 40 hp, 1780 rpm 460 V, 3-phase, 60 Hz drip-proof Baldor Super E premium energy induction motor has a power factor of 86% and a
zysi [14]

Answer:

$26,524.95

Explanation:

In order to figure out how much it costs to drive the motor for 3 years, we must first figure out how many kW there are to the 40hp power of the motor, so we do a conversion:

40Hp*\frac{0.7457kW}{1Hp}=29.828kW

Once we got how many kW there are to the 40Hp, we can now figure out how much electric power the motor is consuming, we can do that by using the efficiency of the motor, so we get:

Power=\frac{29.828kW}{0.921}=32.387kW

Now we can figure out for how many hours the motor is going to be driven throughout the 3 years.

3years*\frac{52weeks}{1 year}*\frac{5days}{1week} *\frac{14hr}{1day}=10,920 hrs[\tex]

now that we got the number of hours the motor will be working, we can now find the number of kWh the motor consumes during the 3 years:

32.387kW*10,920hr=353,666.04kWh

So now we can figure out how much it will cost to drive the motor:

353,666.04kWh*\frac{\$0.075}{1kWh}=$26,524.95

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