B I guess. since they both have potential to collapse
Answer:
1123.6 pounds/ square inch.
Explanation:
Fluid pressure is the ratio of force or weight applied by the fluid per unit area.
i.e Fluid pressure = 
The maximum load of the jack is obtained at its maximum capacity = 5000 pounds
Area of the large piston on the jack = 4.45 square inches
Thus,
Fluid pressure = 
= 1123.5955
Fluid pressure = 1123.6 pounds/ square inch
Thu, the fluid pressure in the jack at maximum load is 1123.6 pounds/ square inch.
Answer:
,
, ![\frac{dv}{dx} = -v_{in}\cdot \left(\frac{1}{L}\right) \cdot \left(\frac{v_{in}}{v_{out}}-1 \right) \cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}} -1 \right) \cdot x \right]^{-2}](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdx%7D%20%3D%20-v_%7Bin%7D%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7BL%7D%5Cright%29%20%5Ccdot%20%5Cleft%28%5Cfrac%7Bv_%7Bin%7D%7D%7Bv_%7Bout%7D%7D-1%20%20%5Cright%29%20%5Ccdot%20%5Cleft%5B1%20%2B%20%5Cleft%28%5Cfrac%7B1%7D%7BL%7D%5Cright%29%5Ccdot%20%5Cleft%28%5Cfrac%7Bv_%7Bin%7D%7D%7Bv_%7Bout%7D%7D%20-1%20%5Cright%29%20%5Ccdot%20x%20%5Cright%5D%5E%7B-2%7D)
Explanation:
Let suppose that fluid is incompressible and diffuser works at steady state. A diffuser reduces velocity at the expense of pressure, which can be modelled by using the Principle of Mass Conservation:




The following relation are found:

The new relationship is determined by means of linear interpolation:


After some algebraic manipulation, the following for the velocity as a function of position is obtained hereafter:


![v (x) = v_{in}\cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1 \right)\cdot x \right]^{-1}](https://tex.z-dn.net/?f=v%20%28x%29%20%3D%20v_%7Bin%7D%5Ccdot%20%5Cleft%5B1%20%2B%20%5Cleft%28%5Cfrac%7B1%7D%7BL%7D%5Cright%29%5Ccdot%20%5Cleft%28%5Cfrac%7Bv_%7Bin%7D%7D%7Bv_%7Bout%7D%7D-1%20%20%5Cright%29%5Ccdot%20x%20%5Cright%5D%5E%7B-1%7D)
The acceleration can be calculated by using the following derivative:

The derivative of the velocity in terms of position is:
![\frac{dv}{dx} = -v_{in}\cdot \left(\frac{1}{L}\right) \cdot \left(\frac{v_{in}}{v_{out}}-1 \right) \cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}} -1 \right) \cdot x \right]^{-2}](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdx%7D%20%3D%20-v_%7Bin%7D%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7BL%7D%5Cright%29%20%5Ccdot%20%5Cleft%28%5Cfrac%7Bv_%7Bin%7D%7D%7Bv_%7Bout%7D%7D-1%20%20%5Cright%29%20%5Ccdot%20%5Cleft%5B1%20%2B%20%5Cleft%28%5Cfrac%7B1%7D%7BL%7D%5Cright%29%5Ccdot%20%5Cleft%28%5Cfrac%7Bv_%7Bin%7D%7D%7Bv_%7Bout%7D%7D%20-1%20%5Cright%29%20%5Ccdot%20x%20%5Cright%5D%5E%7B-2%7D)
The expression for acceleration is derived by replacing each variable and simplifying the resultant formula.