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nignag [31]
3 years ago
15

You can type notes of what to cover when presenting the show in the______ pane.

Computers and Technology
1 answer:
Scorpion4ik [409]3 years ago
5 0
The correct answer to fill in the black is note pane
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Which of the following electronic collaboration techniques is the best
muminat

Answer:

D. project management software

6 0
3 years ago
Read 2 more answers
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
3 years ago
Draw a timeline for each of the following scheduling algorithms. (It may be helpful to first compute a start and finish time for
12345 [234]

Answer:

See explanation below

Explanation:

Previos concepts

First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".

Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".

Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".

Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"

Solution for the problem

Assuming the dataset given on the plot attached.

Part a

For this algorithm the result would be:

Job A   0-6

Job B   6-(6+3) = 6-9

Job C   9-(9+1) = 9-10

Job D   10-(10+4) = 10-14

Part b

For this algorithm the result would be:

Job A   0-6

Job C   6-(6+1) = 6-7

Job B   7-(7+3) = 7-10

Job D   10-(10+4) = 10-14

Part c

For this algorithm the result would be:

Job A   0-1  until 14

Job B   2-(2+3) = 2-5

Job C   3-(3+2) = 3-5

Job D   9-(9+5) = 9-14

Part d

For this algorithm the result would be:

Job A   0-2 , 7-9, 12-14

Job B   2-4, 9-10

Job C   4-(4+1) = 4-5

Job D   5-7, 10-12

8 0
3 years ago
You have just used a command that produced some interesting output on the screen. You would like to save that information into a
Bogdan [553]

Answer: A. > interesting.txt

Explanation: From the command line, one can perform numerous tasks from navigating into a directory, creating a new directory, deleting files, create files, modify files and so on using simple commands. In the scenario above, after using a common which is used to produce an output on the screen, such as the 'echo' command, one may wish to save the file giving the user the ability to access the file later. Since it is stated the file name 'interesting.txt' given to the file does not currently exist, appending the sign > saves the file. If the filename already exists, it will overwrite the existing content.

6 0
3 years ago
Write a program using integers userNum and x as input, and output userNum divided by x three times.
andrezito [222]

Answer:

# The user is prompted to enter number as dividend

# The received number is assigned to userNum

userNum = int(input("Enter the number you want to divide: "))

# The user is prompted to enter number as divisor

# The divisor is assigned to x

x = int(input("Enter the number of times to divide: "))

# divideNumber function is defined to do the division

def divideNumber(userNum, x):

   # counter is declared to control the loop

   counter = 1

   # the while-loop loop 3 times

   # the division is done 3 times

   while counter <= 3:

       # integer division is done

       # truncating the remainder part

       userNum = userNum // x

       # the result of the division is printed

       print(userNum, end=" ")

       # the counter is incremented

       counter += 1

# the divideNumber function is called

# the received input is passed as parameter

# to the function

divideNumber(userNum, x)

# empty line is printed

print("\n")

Explanation:

The // operator in python works like the / operator in C. The // operator returns only the integer part of division operation. For instance 6 // 4 = 1. The fraction part is discarded.

7 0
3 years ago
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