(x-2)^2+20=0
(x-2)^2=-20
If you root both sides you will yield complex numbers (i, imaginary unit is such that i^2=-1),
x-2=20i
x=2+20i
and whenever x is a solution a complex conjugate x* is also a solution,
x*=2-20i
So the answer is A.
Hope this helps :)
-14n>0 i think so it would be just n>0
I can you be a little bit clear I don’t really understand the question.
Answer:
114°
Step-by-step explanation:

If you are trying to find h, then its very simple.
So lets see 5+7=12
So 17-12=5
So lets check to see if h=5
5+5+7
5+5=10+7=17 so h is 5. :)