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iren [92.7K]
3 years ago
5

During the titration of a diluted vinegar sample with a sodium hydroxide solution, the volume of sodium hydroxide used was less

than expected. Which of the following could account for the lower than expected volume?
A. The sodium hydroxide solution had been allowed to stand exposed to the air for a long time prior to the titration.
B. The volumetric flask used to prepare the diluted vinegar solution was rinsed with water prior to use.
C. The burette used to deliver the sodium hydroxide solution was rinsed with water prior to use.
D. The pipette used to deliver the vinegar solution was rinsed with water prior to use.
Chemistry
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

B and D could be true

Explanation:

A volume of sodium hydroxide less than expected could occurs for two reasons:

The real concentration of sodium hydroxide was higher than expected or the amount of vinegar added was less than expected:

A. The sodium hydroxide solution had been allowed to stand exposed to the air for a long time prior to the titration.  FALSE. A long expose  to the air decreases concentration of the NaOH.

B. The volumetric flask used to prepare the diluted vinegar solution was rinsed with water prior to use.  TRUE. You add a less amount of vinegar doing you require less amount of NaOH than expected.

C. The burette used to deliver the sodium hydroxide solution was rinsed with water prior to use.  FALSE. Thus, you add a less amount of NaOH than expected. To explain the matter, you add more NaOH than expected.

D. The pipette used to deliver the vinegar solution was rinsed with water prior to use. TRUE. Again, you are adding a less amount of Vinegar than expected doing the necessary NaOH during titration less than expected

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Element at Extreme Left In Periodic Table:
                                                                   The elements of Group I-A (1) are present at extreme left of the periodic table. They are called as Alkali Metals. Alkali Metals are strong metals. These elements can easily loose their valence electron. The valence shell electronic configuration of these elements is,

                                                     ns¹

where n is principle quantum number, which shows main energy level or shell. These metals can gain Noble gas configuration (stable configuration) either by loosing one electron or by gaining seven or more electrons. As it is quite reasonable to loose one electron instead of gaining seven or more electrons so these element easily loose one electron to gain noble as configuration. The Metallic character decreases along the period from left to right. So Group II-A (2) are second most metallic elements and so on. These metals at extreme left mainly exist in solid form.

Element at Extreme Right In Periodic Table:
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5 0
3 years ago
What is the importance of standardization in chemistry​
Anika [276]

Answer:

Standardisation is used to determine the concentration of a volumetric solution in order to achieve accurate and reliable titration results

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Answer:

A.

Explanation:

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3 years ago
An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li
tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

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4 0
2 years ago
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Firlakuza [10]

Answer:

Here's what I get.

Explanation:

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Bottom line: ask your teachers in advance what they expect.

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3 years ago
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