It's unable to identify a decrease in LOS linked to corticosteroid exposure during hospitalization for ocular cellulitis in this database search. After two days of hospitalization, operational episodes and the prescription of corticosteroids were related to admission to the PICU.
Within two days of admission, 1347 (24%) of the 5462 children who were included in the research received a corticosteroid prescription. In analyses that controlled for age, the existence of meningitis, abscess, or visual problems, as well as the surgical episode and PICU admission within 2 days, corticosteroid prescription was not linked with LOS (e = 1.01, 95% confidence interval [CI]: 0.97-1.06). Among patients with a primary diagnosis of orbital cellulitis, corticosteroid exposure was linked to surgical events after two days of hospitalization (odds ratio = 2.05, 95% CI: 1.29-3.27) and 30-day readmission (odds ratio = 2.40, 95% CI: 1.52-3.78). Prospective, randomized control trials are required prior to the widespread usage of corticosteroids.
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The correct option is A.
To calculate the binding energy, you have to find the mass defect first.
Mass defect = [mass of proton and neutron] - Mass of the nucleus
The molar mass of thorium that we are given in the question is 234, the atomic number of thorium is 90, that means the number of neutrons in thorium is
234 - 90 = 144.
The of proton in thourium is 90, same as the atomic number.
Mass defect = {[90 * 1.00728] +[144* 1.00867]} - 234
Note that each proton has a mass of 1.00728 amu and each neutron has the mass of 1.00867 amu.
Mass defect = [90.6552 + 145.24848] - 234 = 1.90368 amu.
Note that the unit of the mass is in amu, it has to be converted to kg
To calculate the mass in kg
Mass [kg] = 1.90368 * [1kg/6.02214 * 10^-26 = 3.161135 * 10^-27
To calculate the binding energy
E = MC^2
C = Speed of light constant = 2.9979245 *10^8 m/s2
E = [3.161135 * 10^-27] * [2.9979245 *10^8]^2
E = 2.84108682069 * 10^-10.
Note that we arrive at this answer because of the number of significant figures that we used.
So, from the option given, Option A is the nearest to the calculated value and is our answer for this problem.
1 milliliters in one milligram.
Oxygen hydrogen helium argon xenon krypton
neon nitrogen radon chlorine bromine fluorine
