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hichkok12 [17]
3 years ago
12

What are some important things in this paragraph ???? BRAINLIST WILL BE AWARDED!

Chemistry
1 answer:
mezya [45]3 years ago
6 0

Answer:

Suppose you were standing in the dark room with a bare light bulb behind you. You hold a ball in front of you, and you can see all of the lit half of the ball, which looks like a circle.

you rotate 90° to your left, and see the left side of the circle lit while the right side is dark. Half the ball is still lit up, but you can see only part of the lit area. As you continue to rotate, you see a different amount of the ball. In fact, you would see the shape change from a full circle to a crescent shape to a backwards crescent shape and then back to a full circle.

Explanation:

I think this is it tell me if i'm wrong

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ENTHALPY! Please Help
Alexus [3.1K]

hey it wont let me go to page

7 0
3 years ago
Read 2 more answers
Which term best describes this reaction? 2 carbons double bonded to each other, with CH 3 above the left C and H above the right
Ierofanga [76]

Answer:

addition polymerization

Explanation:

In addition polymerization, the monomers are simply joined to each other to form a polymer having the same empirical formula as the monomer but of higher relative molecular mass. The monomers in addition polymerization are usually simple unsaturated molecules such as alkenes.

We can deduce the reaction to be an addition polymerization because of the the attachment of n to both the unsaturated monomer and the saturated polymer without the loss of any small molecule. If it was a condensation polymerization, there would have been an accompanying loss of a small molecule such as water.

6 0
4 years ago
What is the freezing point of a solution that contains 36.0 g of glucose in 500.0 g of water (Kf for water is 1.86C/m. The molar
lbvjy [14]
This freezing point business is usually based on molality, that is moles solute per kilogram of solvent. 

<span>molality = freezing point depression over Kf </span>

<span>In this case molality -10.3 degrees over -1.85 degrees Kf = 5.53 molal </span>

<span>This 5.53 molal solution is made up of l000 gms water and 5.53 moles glucose at 180 grams per mole for a total mass of 1997 grams </span>

<span>It volume would be l997 gms over 1.50 gms/ml or 1331 ml </span>

<span>We know that we have 5.53 moles of glucose dissolved in l331 ml of solution so now we can find how many moles of glucose in l000 ml or one liter of solution and this will be our Molarity </span>

<span>5.53 moles glucose over l331 ml = X moles glucose over l000 ml solution </span>

<span>cross multiply and solve for X moles glucose per liter solution </span>

<span>X = 4.15 moles glucose per liter = 4.15 Molar</span>
5 0
4 years ago
Alpha Decay
Inessa [10]

Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.

<h3>What are the products of Uranium-238 and Thorium -228?</h3>

If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.

So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.

Learn more about isotope here: brainly.com/question/14220416

#SPJ1

4 0
3 years ago
How do the following changes affect the value of the equilibrium constant for a gas-phase exothermic reaction:
mr Goodwill [35]

Answer:

A. increase equilibrium constant                    

B. decrease equilibrium constant

A. increase equilibrium constant

C. no effect

B. decrease equilibrium constant

Explanation:

5 0
3 years ago
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