To produce 56.6 kg of oxygen, moles of KNO₃ = 142.915 kg
This is a stoichiometric kind of question where everything should be converted into moles in order to proceed on with the calculations.
First you find the number of moles of oxygen using the following formula:
Mole (mol) = Mass (g) / Molar Mass (g/mol)
For oxygen, the molar mass is 32g/mol.
Therefore the number of moles in 56.6 kg of oxygen is :
(56.6 × 1000)/32
= 1768.75
From the reaction equation, the ratio of to O2 is 4:5.
Thus the number of moles of is
1768.75 × 4/5
= 1415 mol.
If you are looking for the mass of needed then Mass (g)
= Mole (mol) × Molar Mass (g/mol),
1415 ×101 = 142,915g
= 142.915kg
What happens to potassium nitrate when heated?
When potassium nitrate is heated, it decomposes into potassium nitrite and oxygen. Write a balanced equation for this reaction and add the state symbols of the reactants and products.
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