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Ratling [72]
3 years ago
5

Help help (12 points)

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0

Answer:

2m+2m

Step-by-step explanation:

Maurinko [17]3 years ago
3 0

Answer:

2

Step-by-step explanation:

m+m+m+m=4m

4m-2m=2m

_m=2m

2

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Hannah says that 2.11 is a rational number. Gus says that 2.11 is a repeating decimal. Who is correct and why?
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  • 2.11 is rational number Hannah is correct because it doesn't have 3 dots in the end if it is repeating decimal it will be (2.11.......
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Find the length of a rectangle if its
Alina [70]

Answer: L = 29cm

Step-by-step explanation:

Let's go!!

To find any rectangle area, you have to apply this formula: A = L . w , where L is the length and w is the width.

So, we have w = L - 13 (the width is 13 less than the Length) and then, perimeter is 90 cm.

Well, I hope you remember that the perimeter of rectangle is 2L + 2W. In this case, 2L + 2w = 90

Then, you might to solve this system of equation:

2L + 2w = 90

w = L - 13

Simplifying the first equation, you'll have L + w = 45 (you can divide everything of 2).

Our new system:

L + w = 45

w = L - 13

Using the substituition method:

L + L - 13 = 45

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the width is 29 - 13 = 16 cm

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Machine A and machine B both make car parts.
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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
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