The expression -> 4 • 2 - 3
the answer to the expression would be 5
I believe the answer is x⁢10 if it’s incorrect i’m so sorry
The foctor of 40 I this = 1,2,4,5,8,40
Answer:
- slope: 1
- equation: y = x +3
Step-by-step explanation:
The slope of the line between two points can be found using the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (2 -0)/(-1 -(-3)) = 2/2
m = 1 . . . . . the slope of the line is 1
__
The value of the y-intercept can be found by solving the slope-intercept equation for b.
y = mx +b
b = y -mx
b = (0) -(1)(-3) = 3 . . . . . using point (x, y) = (-3, 0)
The equation of the line with slope 1 and y-intercept 3 can be written as ...
y = x +3
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
