Answer:
2m + 10n - 2p
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(4m + 7n - 6p) - (2m - 3n - 4p)
<u>Step 2: Simplify</u>
- Distribute negative: 4m + 7n - 6p - 2m + 3n + 4p
- Combine like terms (m): 2m + 7n - 6p + 3n + 4p
- Combine like terms (n): 2m + 10n - 6p + 4p
- Combine like terms (p): 2m + 10n - 2p
(-) Tỉ số độ dài 2 cạnh là 5 và 7
=> Chiều rộng = 5:12, chiều dài = 7:12
(-) Chu vi = 240 suy ra tổng chiều dài + chiều rộng = 240 : 2 = 120
(-) Chiều rộng = 120 x 5 : 12 = 50
Chiều dài = 120 x 7 : 12 = 70
(-) Diện tích = 50 x 70 = 3500
Another way to name one forth is to say that he coloured a quarter of the rectangle because a quarter is one forth
hope that helps
In the above problem, you want to find the number of multiples of 7 between 30 and 300.
This is an Arithmetic progression where you have n number of terms between 30 and 300 that are multiples of 7. So it is evident that the common difference here is 7.
Arithmetic progression is a sequence of numbers where each new number in the sequence is generated by adding a constant value (in the above case, it is 7) to the preceding number, called the common difference (d)
In the above case, the first number after 30 that is a multiple of 7 is 35
So first number (a) = 35
The last number in the sequence less than 300 that is a multiple of 7 is 294
So, last number (l) = 294
Common difference (d) = 7
The formula to find the number of terms in the sequence (n) is,
n = ((l - a) ÷ d) + 1 = ((294 - 35) ÷ 7) + 1 = (259 ÷ 7) + 1 = 37 + 1 = 38
