The sediment left behind by a glacier is typically
2 answers:
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Answer: 0.745 g of will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require=
of
Mass of
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
The mass decay rate is of the form
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.
Because the half-life is 30 years, therefore
After 60 years, the mass remaining is
Answer: 750 g
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.
Because the half-life is 30 years, therefore
After 60 years, the mass remaining is
Answer: 750 g