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sergey [27]
4 years ago
13

If equal masses of aluminum and copper are heated with same amount of heat, which would reach the higher temperature? Explain yo

ur answer .
Chemistry
1 answer:
Anestetic [448]4 years ago
3 0

Answer:

copper will reach to higher temperature first.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,

The specific heat capacity of copper is 0.386 j/g. K and for aluminium is 0.900 j/g.K. So, aluminium take a time to increase its temperature by one degree by absorbing more heat while copper will heat up faster by absorbing less amount of heat.

Consider that both copper and aluminium have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,

For copper:

Q = m.c. ΔT

Q = 5 g× 0.386 j/g K × 15 K

Q = 28.95 j

For aluminium:

Q = m.c. ΔT

Q = 5 g× 0.900 j/g K × 15 K

Q = 67.5 j

we can observe that aluminium require more heat which is 67.5 j to increase its temperature.  So it will reach to higher temperature later as compared to copper.

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What causes each new row of the periodic table
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Answer:

elements have the same number of valence electrons and similar chemical properties.

Explanation:

they have the same number

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4 years ago
When discussing discordant and harmonious sound waves, which statement is false?
notka56 [123]
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hope this helps
3 0
3 years ago
Suggest why sodium and hydrogen ions do not diffuse at the same rate
Troyanec [42]

Answer:

sodium has got ionic bonds that are weak

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8 0
3 years ago
1‑propanol ( nn ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure
likoan [24]

Answer:

Piso = 32.17 Torr

Pprop = 5.079 Torr

yprop = 0.1364

yiso = 0.8636

Explanation:

From the question; we can opine that :

  • The mole fraction of isopropanol in a mixture of isopropanol and propanol will be 1.
  • The partial pressure of isopropanol will be its mole fraction multiplied by vapor pressure of isopropanol
  • The partial pressure of propanol will be its mole fraction multiplied by vapor pressure of propanol
  • In the vapor, the mole fraction of propanol will be its partial pressure divided by the sum of the two partial pressures      

NOW;

When xprop = 0.243; xisopropanol will be 1- 0.243 = 0.757

P°iso = 45.2 Torr at 25 °C so

Piso will be 45.2 × 0.757 = 32.17 Torr

Pprop will be 20.9 × 0.243 = 5.079 Torr

yprop = 5.079/(5.079 +32.17) = 0.1364

yiso = 1-0.1364 = 0.8636

5 0
3 years ago
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