Answer:
Atoms He (Avogadro’s number) → Moles of He (molar mass of He) → Mass of He
• molar mass of He (from the periodic table) = 4.003 g/mol
• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole: 6.022 × 1023 He atoms in 1 mole of He
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A change in temperature is called a temperature change
When heat energy at a constant pressure = the change of enthalpy
ΔH = Q
and when the internal energy of an ideal gas formula is:
ΔH = n.Cp.ΔT
and when Cp = (5/2) R at a constant pressure of a monatomic ideal gas
∴Q = n.(5/2).R.ΔT
∴ ΔT = Q / [n.(5/2).R]
when Q is the heat required = 43.08 J (given)
and n is no.of moles = mass / molar mass
= 1.1 g / 39.948 g/mol
= 0.0275 moles
and R is gas constant = 8.314472J/mol K
by substitution:
ΔT = 43.08 J / (0.0275moles *(5/2) * 8.314472 J/mol K
= 76.76 K
1) Write the balanced chemical equation
4NH3 + 5O2 ----> 4NO + 6H2O
2) Write the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Write the proportions with the desired quantity of NO and the unknown quantity of O2
5 mol O2 / 4 mol NO = x / 18.0 mol NO
Solve for x: x = 18.0 mol NO * 5 mol O2 / 4 mol NO = 22.5 mol O2
4) Use the ideal gas equation to convert moles to volume
pV = nRT => V = nRT / p
n = 22.5 mol
R = 0.082 atm*liter / K * mol
T = 33 + 273.15 = 306.15 K
p = 874/760 atm = 1.15 atm
V = 22.5 mol * 0.082 atm*liter/K*mol * 306.15 K / 1.15 atm = 491.17 liter
Answer: 491 liters of O2
Answer:
Explanation:
In this problem, a 10 - 10 M solution of HCl contributes 10 - 10 M [H +]. The ionization of water contributes 10 - 7 M [H +].
