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joja [24]
3 years ago
11

What can be used to plot the magnetic field around a bar magnet?

Physics
1 answer:
zlopas [31]3 years ago
4 0

Answer:

A bar magnet creates a magnetic field around it. The field cannot be seen, but its effects can be observed. This is how the magnetic field around a magnet is detected. Iron fillings can be used to study the presence of magnetic field and a compass can be used to plot the field lines.

Explanation:

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20 times the number of hours
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What does gravitational potential energy depend on
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Calculate the volume that 42g of nitrogen gas (N2)occupies at standard temperature and pressure.​
luda_lava [24]

Nitrogen gas has a molar mass of about 28.0134 g/mol. Then we have a starting amount of

(42 g) / (28.0134 g/mol) ≈ 1.4993 mol

of N₂.

At standard temperature and pressure, one mole of an ideal gas occupies a volume of about 22.4 L. Then 42 g, or 1.4993 mol, of N₂ takes up

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8 0
3 years ago
A charge of 1.0 × 10-6 μC is located inside a sphere, 1.25 cm from its center. What is the electric flux through the sphere due
Korvikt [17]

Answer:

\Phi_E=0.11\frac{N\cdot m^2}{C}

Explanation:

According to Gauss's Law, the electric flux of a charged sphere is the electric field multiplied by the area of ​​the spherical surface:

\Phi_E=EA\\\Phi_E=E(4\pi R^2)\\\Phi_E=\frac{q}{4\pi \epsilon_0 R^2}(4\pi R^2)\\\Phi_E=\frac{q}{\epsilon_0}

This is identical to the electric flux of a point charge located in the center of the sphere.

\Phi_E=\frac{1*10^{-12}C}{8.85*10^{-12} \frac{C^2}{N\cdot m^2}}\\\Phi_E=0.11\frac{N\cdot m^2}{C}

8 0
4 years ago
Calculate the magnitude of the force between two 3.60 mC point challenges 9.3 cm apart
vladimir1956 [14]

Q = magnitude of charge on each of the two point charge = 3.60 mC = 3.60 x 10⁻³ C

r = distance between the two point charges = 9.3 cm = 0.093 m

k = constant = 9 x 10⁹ Nm²/C²

F = magnitude of the force between the two point charges = ?

according to coulomb's law , force between two charges is given as

F = k Q²/r²

inserting the values

F = (9 x 10⁹) (3.60 x 10⁻³)²/(0.093)²

F = 1.35 x 10⁷ N

3 0
3 years ago
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