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STatiana [176]
3 years ago
14

The force of attraction between a ball is F=.........×10^-¹¹

Physics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

4.45×10¯¹¹ N

Explanation:

From the question given above, the following data were obtained:

Mass of ball (M₁) = 4 Kg

Mass of bowling pin (M₂) = 1.5 Kg

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Distance apart (r) = 3 m

Force of attraction (F) =?

The force of attraction between the ball and the bowling pin can be obtained as follow:

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 4 × 1.5 / 3²

F = 4.002×10¯¹⁰ / 9

F = 4.45×10¯¹¹ N

Therefore, the force of attraction between the ball and the bowling pin is 4.45×10¯¹¹ N

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Naomi is taking a train from DC to New York which is 360km apart. If the train is traveling at an average speed of 32 meters per
rodikova [14]

Answer:

11250 seconds or 187.5 mins

Explanation:

The formula to be used here is that of speed.

Speed (in m/s) = distance (meter) ÷ time (secs)

The speed provided is 32 meters per second

The distance provided will have to be converted to meters; 360 km = 360 × 1000 = 360000 meters

Thus,

32 = 360000 ÷ time

time = 360000 ÷ 32

time = 11250 seconds or 187.5 mins

It will take Naomi 11250 seconds to get to New York

4 0
2 years ago
What is the purpose of an experiment design?
Eddi Din [679]
An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
5 0
3 years ago
Distinguishing between Speed and Velocity.
koban [17]

Answer:

Speed: Distance per time, 400 km/h, and a scalar quantity.

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Explanation:

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8 0
3 years ago
PLS HELP! If you are given force and distance, you can determine power if you know (2 points)
Lisa [10]

Answer:

C. Time

Explanation:

6 0
3 years ago
Read 2 more answers
1. Determine the image distance in each of the following.
miskamm [114]

It is given that for the convex lens,

Case 1.

u=−40cm

f=+15cm

Using lens formula

v

1

−

u

1

=

f

1

v

1

−

40

1

=

15

1

v

1

=

15

1

−

40

1

v=+24.3cm

The image in formed in this case at a distance of 24.3cm in left of lens.

Case 2.

A point source is placed in between the lens and the mirror at a distance of 40 cm from the lens i.e. the source is placed at the focus of mirror, then the rays after reflection becomes parallel for the lens such that

u=∞

f=15cm

Now, using mirror’s formula

v

1

+

u

1

=

f

1

v

1

+

∞

1

=

15

1

v=+15cm

The image is formed at a distance of 15cm in left of mirror

6 0
3 years ago
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