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valentina_108 [34]
3 years ago
10

Help please this problem thank you

Mathematics
1 answer:
tangare [24]3 years ago
8 0
The value of x is 25.
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Find the amount of interest on $35,000 at 9.72% compounded monthly for 32 months
zhannawk [14.2K]

9514 1404 393

Answer:

  $10,308.92 interest earned

Step-by-step explanation:

The account balance is given by ...

  A = P(1 +r/12)^n

where principal P earns interest at annual rate r compounded monthly for n months. In this case, the balance would be ...

  A = $35,000(1 +0.0972/12)^32 = $45,308.92

The interest earned is the excess of the balance over the original investment:

  interest = $45,308.92 -35,000 = $10,308.92

4 0
3 years ago
Help!!plzzzzzzzzzz!!ASAP!!
katrin2010 [14]
A and B are congruent. 
4 0
3 years ago
Help?
Kazeer [188]
Remember, h(x) = y and x ...well, x is x...lol

B. h(x) = |x|....subbing in (-1,1)
     y = |x|
     1 = |-1|...absolute values are positive, even when they say negative
     1 = 1 (correct)
8 0
3 years ago
Jose an airline pilot, flies 1,350 miles a day.how many miles will he fly in 8 days?
AURORKA [14]
10,800 :) 8 multiplied by 1,350 would give you 10,800 miles.
6 0
3 years ago
Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi
Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:


\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m


\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m


Therefore:

\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m


So:

\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)


Finally, the magnitude is:


\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}

7 0
3 years ago
Read 2 more answers
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