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inna [77]
3 years ago
12

1. A stone is thrown upwards with an initial velocity of 25 m/s at angle of 30° to the ground a. Show that the vertical componen

t if the velocity at the starting is 12.5 m/s upwards.
Physics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

sin 30° = \frac{v_{y} }{25}

Multiply each side by 25 to cancel the 25 under v_{y}

(25)· sin 30° = v_{y}

Multiply everything on the left side.

12.5 \frac{m}{s} = vertical velocity component.

I attached a picture, I hope it helps.

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bija089 [108]

Cathode rays are negatively charged

Explanation:

Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.

Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.

One notable one was that he observed that the rays deflected towards the positively charged plate.

Since unlike poles attract then he concluded that the cathode rays were negatively charged.

learn more:

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6 0
3 years ago
Which of the following terms refers to energy that is stored; for example the gravitational energy of water behind a dam:
kolezko [41]
Answer is Potential Energy (A)
4 0
4 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
3 years ago
Calculate the GPE of a rock with a mass of 55kg on a cliff that is 27m high
GaryK [48]

Answer:

<em>P=mgh</em>

<em>P=mghm=55</em>

<em>P=mghm=55g=9.8 or ~10</em>

<em>P=mghm=55g=9.8 or ~10h=27</em>

Explanation:

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4 0
2 years ago
Can carrying an object be said to be doing work on that object?
Schach [20]

Answer:

Only if that object is being moved while carried

Explanation:

Work = Force • distance travelled

While holding an object would need force equal to that objects mass multiplied by 9.8, if it hasn't moved, then no work is done.

if you were to carry the object and have it travel some distance, then work would be done on that object.

7 0
3 years ago
Read 2 more answers
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