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inna [77]
3 years ago
12

1. A stone is thrown upwards with an initial velocity of 25 m/s at angle of 30° to the ground a. Show that the vertical componen

t if the velocity at the starting is 12.5 m/s upwards.
Physics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

sin 30° = \frac{v_{y} }{25}

Multiply each side by 25 to cancel the 25 under v_{y}

(25)· sin 30° = v_{y}

Multiply everything on the left side.

12.5 \frac{m}{s} = vertical velocity component.

I attached a picture, I hope it helps.

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Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
Sedaia [141]

Answer:

a_2\ =\ -33.65\ m/s^2

Explanation:

Given,

For the first rocket,

  • Initial velocity of the first rocket A = u_1\ =\ 4600\ m/s.
  • Acceleration of the first rocket = a_1\ =\ -18\ m/s^2

For the second rocket,

  • Initial velocity of the second rocket B = u_2\ =\ 8200 m/s.
  • Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec

Let a_2 be the acceleration of the second rocket B for the same time interval

from the kinematics,

\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\

\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0
3 years ago
In a football game, a 96 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi
fredd [130]

Answer:

V = 0.074 m/s

Explanation:

given,

mass of the receiver, M = 96 Kg

mass of the ball, m = 0.42 Kg

initial speed of the ball, v = 17 m/s

initial speed of the receiver = 0 m/s

final speed.V = ?

using conservation of momentum

M u + m v = (M + m) V

0 + 0.42 x 17 = (96+0.42) V

96.42 V = 7.14

V = 0.074 m/s

hence, Speed after catching the ball is equal to 0.074 m/s

7 0
4 years ago
A 1.0 kg ball falls from rest a distance of 15 m. what was its change in potential energy?
patriot [66]

Answer:

147 J

Explanation:

PE = mgh

PE = (1.0)(9.8)(15)

PE = 147 joules

7 0
3 years ago
A child pulls on a wagon with a force of 75 N. If the wagon moves a total of 42 m in 3.1 min, what is the average power delivere
exis [7]

Answer:

16.96 W

Explanation:

Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

From the question,

P = (F×d)/t....................... Equation 1

Where P = power, F = force, d = distance, t = time.

Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s

Substitute these values into equation 1

P = (75×42)/186

P = 16.94 W

Hence the average power delivered by the child  = 16.96 W

4 0
3 years ago
When discussing distances between objects in the solar system, which term do you use?
Bond [772]
I think it's (ASTRONOMICAL UNIT)

Explanation:
It is used to compare the distances of other bodies in the Solar System, such as the Sun, the planets, comets, and asteroids.
8 0
2 years ago
Read 2 more answers
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