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Zinaida [17]
2 years ago
14

When discussing distances between objects in the solar system, which term do you use?

Physics
2 answers:
Bond [772]2 years ago
8 0
I think it's (ASTRONOMICAL UNIT)

Explanation:
It is used to compare the distances of other bodies in the Solar System, such as the Sun, the planets, comets, and asteroids.
ANEK [815]2 years ago
4 0
D) Relative Distance
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Healthy blood vessels do what more easily? open close or move
Viktor [21]
They open more easily.
8 0
4 years ago
Read 2 more answers
What is a combination of symbols that shows the ratio of elements in a compound
Alex_Xolod [135]
The combination of symbols that shows the ratio of elements in a compound is called chemical formula. A chemical formula is one of the ways in expressing information about the ratio and proportion of atoms that consists a particular chemical compound. This is done by using a single line pf chemical symbols of elements, numbers, and sometimes parentheses, comma, dashes, brackets and sometimes the positive and negative sign. Chemical formula can completely specify the simplest structure of molecules and chemical substances.


8 0
3 years ago
If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?
andreyandreev [35.5K]

Answer:

v = -6m/s

Explanation:

x=4-12t+3t^2

\frac{dx}{dt}=-12+6t

For t = 1:

\frac{dx}{dt}=-6

3 0
3 years ago
A 50 gram meterstick is placed on a fulcrum at its 50 cm mark. A 20 gram mass is attached at the 12 cm mark. Where should a 40 g
alekssr [168]

Answer:

The 40g mass will be attached at 69 cm

Explanation:

First, make a sketch of the meterstick with the masses placed on it;

--------------------------------------------------------------------------

               ↓                    Δ                      ↓

             20 g.................50 cm.................40g

                         38 cm                  y cm  

Apply principle of moment;

sum of clockwise moment = sum of anticlockwise moment

40y = 20 (38)

40y = 760

y = 760 / 40

y = 19 cm

Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm

              12cm             50 cm              69cm

--------------------------------------------------------------------------

               ↓                    Δ                      ↓

             20 g.................50 cm.................40g

                         38 cm                 19 cm                                              

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

5 0
3 years ago
shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const
Contact [7]

Answer:

a) T=0.40 N

b) T=1.9 s

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

P=2\pi r=0.94

r=\frac{0.94}{2\pi}=0.15 m

Now, we need to find the angle of the pendulum from vertical.

tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17

\alpha=9.44 ^{\circ}

Let's apply Newton's second law to find the tension.

\sum F=ma_{c}=m\omega^{2}r

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

Tcos(\alpha)=mg (1)

The horizontal equation of motion will be:

Tsin(\alpha)=m\omega^{2}r (2)

a) We can find T usinf the equation (1):

T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N

We can find the angular velocity (ω) from the equation (2):

\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s

b) We know that the period is T=2π/ω, therefore:

T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s

I hope it helps you!

8 0
3 years ago
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