Question

In a football game, a 96 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vigorous 17 m/s, catching the ball at the highest point in his jump. Part A Right after catching the ball, how fast is the receiver moving?

Answer 1

Answer:

V = 0.074 m/s

Explanation:

given,

mass of the receiver, M = 96 Kg

mass of the ball, m = 0.42 Kg

initial speed of the ball, v = 17 m/s

initial speed of the receiver = 0 m/s

final speed.V = ?

using conservation of momentum

M u + m v = (M + m) V

0 + 0.42 x 17 = (96+0.42) V

96.42 V = 7.14

V = 0.074 m/s

hence, Speed after catching the ball is equal to 0.074 m/s