How do i solve for A=1/2πr2 (for π)
2 answers:
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Answer:
D. 420
The area of a triangle is
half of(base× height)
10×16= 160
160÷2=80
That is the surface area of ONE triangle.
multiply 80 by 4 to get 320
then find the surface area of the square by doing length×width to get 100
Finally add them together
320+100=420
Step-by-step explanation:
Hey there!
Follow the steps to get answer.
- Use one point formula and find 1st equation.
- After that you find the slope of second equation.
- Use the condition of perpendicular lines and find the slope of first equation.
- Put slope value of equation in equation (i) and simplify them to get equation.
The equation of a line passing through point (2,3) is;
(y-3)= m1(x-2).......(i).
Another equation is;
2nd equation..
Now, From equation (ii)
We have;
Comparing equation (ii) with y = mx+c.
We get;
Slope = -1/2.
For perpendicular lines,
Therefore the slope is 2.
Put value of slope (m1) in equation (i). We get;
Simplify them to get equation.
Therefore the required equation is y = 2x-1.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>