Answer:
- 3 (die)
- 4 (slips)
- 6 (spinner)
- 5 (ace)
Step-by-step explanation:
Josie rolls a six-sided die 18 times. What is the estimated number of times she rolls a two? 3 = (1/6)(18)
Slips of paper are numbered 1 through 10. If one slip is drawn and replaced 40 times, how many times should the slip with number 10 appear? 4 = (1/10)(40)
A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white. If the spinner is spun 30 times, how many times should it land on a red space? 6 = (2/10)(30)
A card is picked from a standard deck of playing cards 65 times and replaced each time. About how many times would the card drawn be an ace? 5 = (4/52)(65)
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The probability of a given event is the number of ways it can occur divided by the number of possibilities. For example, a 2 is one of 6 numbers on a die, so we expect its probability of showing up to be 1/6. The expected number of times it will show up in 18 rolls of the die is (1/6)(18) = 3.
(72÷2)³ - 7 · 9 ÷ 9
First, parenthesis
72÷2 is 36
Next, exponents.
36³ is 46656.
Then, multiplication.
7 · 9= 63
After that, division.
63 ÷ 9 is 7
Finally, subtraction.
46656 - 7 is 46649
9514 1404 393
Answer:
- figure the areas of the rectangle and semicircle
- add them together
Step-by-step explanation:
The area of the rectangle is given by ...
A = LW
A = (20 m)(14 m) = 280 m²
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The area of the semicircle is ...
A = (1/2)πr²
A = (1/2)π(7 m)² = 24.5π m² ≈ 77 m²
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Then the total area is ...
280 m² +77 m² = 357 m²
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The width of the rectangle is the diameter of the circle, which is twice its radius. The area of a semicircle is 1/2 the area of a circle.
Answer:
7
Step-by-step explanation:
edge
