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Marianna [84]
3 years ago
12

Calculate the total energy required to break all the bonds in:

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Explanation:

a. O+ 2=O2

b. C2+h2=CH4

c. C2+H6= C2H6

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Identify the parts of the atom that are labeled in the diagram
baherus [9]

Answer:

A- Nucleus

B-Energy levels

Explanation:

  • An atom refers to the smallest particle of an element that can take part in a chemical reaction.
  • An atom is made up of two major parts namely; the nucleus and the energy shell or energy levels.
  • The nucleus of an atom contains the sub atomic particles, protons and neutrons while the energy shells contain the sub atomic particle electrons.
  • It is important to note that the protons in the nucleus are positively charged which makes the nucleus to be positively charged.
  • On the other hand, energy shells are negatively charged because of the negative charge of the electrons.
6 0
3 years ago
Read 2 more answers
A 50.0 mg sample of iodine-131 was placed in a container 32.4 days ago. if its half-life is 8.1 days, how many milligrams of iod
sertanlavr [38]

3.124mg of I-131 is present after 32.4 days.

The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.

What is Half life?

The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Half of the iodine-131 will still be present after 8.1 days.

The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.

The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.

If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.

Learn more about the Half life of radioactie element with the help of the given link:

brainly.com/question/27891343

#SPJ4

7 0
1 year ago
A gas is collected over water at a certain temperature. The total pressure is 762. mmHg. The vapor pressure of water at this tem
ehidna [41]

I Believe The Answer Is D.

5 0
3 years ago
Read 2 more answers
The density of gold is 19.32 g/mL. What is the volume, in mL, of a nugget of gold with a mass of 55.07 g?
Vika [28.1K]

Answer: 2.850

Explanation:

19.32=\frac{55.07}{v}\\19.32v=55.07\\v=\frac{55.07}{19.32}=\boxed{2.850 \text{ mL}}

5 0
2 years ago
What is the temperature difference if 300 cal are used to warm water
PIT_PIT [208]

Answer:

<u>The temperature difference is</u> \frac{300}{m} Kkg^{-1}

Explanation:

The formula that is to used is :

ΔQ=msΔT

<em>where ,</em>

  • <em>ΔQ is the heat supplied in calories = 300cal</em>
  • <em>m is the mass of water taken = m (assumed)</em>
  • <em>ΔT is the change in temperature</em>
  • <em>s is the specific heat of water = 1calK^{-1}Kg^{-1}</em>

ΔT :

\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}

6 0
3 years ago
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