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3 years ago

Please help! 10 points

Chemistry

1 answer:

myrzilka [38]3 years ago

4 0

Answer:

<u>1 mole of Fe and 1.5 moles of CO2</u>

Explanation:

This is a trick question. The equation is not balanced properly. To start, note that one molecule of Fe2O3 contain 2 Fe atoms, while there is only 1 Fe atom on the product side. And the oxygens are also missing (from 4 to 2). We cannot use this equation, as written.

Here's one that is balanced:

<u>I'll use this one to answer the question.</u>

1. <u>If 3 moles of Fe2O3 react with 1.5 moles of CO, how many moles of each product are formed?</u>

The balanced equation tells us that 1 mole of Fe2O3 will react with 3 moles CO to produce 2 moles of Fe and 3 moles of CO2. <u><em>If we had enough CO</em></u>, 3 moles Fe2O3 will produce 6 moles of Fe and 9 moles of CO2. But note that we'd also need 9 moles of CO for a complete reaction. We only have 1.5 moles, probably due to Stanley, our new manager. So we're limited by the CO, and we'll have to delete our first analysis and work from 1.5 moles of CO.

<h2>If we have 1.5 moles CO, we'll produce:</h2><h2> <u>1 mole of Fe and 1.5 moles CO2.</u></h2>

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4Fe + 3O2 → 2Fe2O3

Black_prince [1.1K]

n(2Fe2O3)=10g/319.374amu=0.03mol

n(4Fe+3O2)=0.03 mol

m(4Fe+2O2)=Mn=319.374×0.03=9.58=10

7 0

3 years ago

Read 2 more answers

1. How many moles of nitrogen gas are in 1.54x10^26 molecules? How many atoms?

kow [346]

Answer:

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1. How many moles of nitrogen gas are in 1.54x10^26 molecules? How many atoms?

2. How many molecules of water are in 3.45 moles of water?

3. How many atoms of C are in 2.00 moles of Cv6Hv12Ov6? (v means the number is below)

Explanation:

6 0

3 years ago

A chemical factory is making soda ash (NA2CO3) from sodium bicarbonate. The production manager calculates they will make 80 tons

grigory [225]

Answer:

$\boxed{\text{ 93 \%}}$

Explanation:

$\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}$

Data:

$\begin{array}{rcr}\text{Actual yield} & = & \text{74.3 T}\\\text{Theoretical yield} & = & \text{80 T}\\\end{array}$

Calculation:

$\text{\% yield} = \dfrac{\text{74.3 T}}{\text {80 T}} \times\text{100 \%} = \textbf{93 \%}}\\\\\text{The percent yield was } \boxed{\textbf{93 \%}}$

7 0

3 years ago

Question 13: Consider the strength of the Hβ absorption line in the spectra of stars of various surface temperatures. This is th

finlep [7]

Answer:

The absorption and strength of the H-beta lines change with the temperature of the stellar surface, and because of this, one can find the temperature of the star from their absorption lines and strength. To better comprehend, let us look into the concept of the atom's atomic structure.

Atoms possess distinct energy levels and these levels of energy are constant, that is, the temperature has no influence on it. However, temperature possesses an influence on the electron numbers found within these levels of energy. Therefore, to generate an absorption line of hydrogen in the electromagnetic spectrum's visible band, the electrons are required to be present in the second energy level, that is when it captivates a photon.

Therefore, after captivating the photons the electrons jump from level 2 to level 4, which shows that there is an increase in the stellar surface temperature and at the same time one can witness a decline in the strength of the H-beta lines. In case, if the temperature of the surface increases too much, then one will witness no attachment of electron with the hydrogen atom and thus no H lines, and if the temperature of the surface becomes too low, then the electrons will stay in the ground state and no formation of H lines will take place in that condition too.

Hence, to generate a very robust H line, after captivating photons the majority of the electrons are required to stay in the second energy level.

5 0

3 years ago

What is the Kelvin temperature of the air in a tire if the pressure inside the tire is 188 kPa at 32°C. While driving under peri

DENIUS [597]

Answer:

<u>414K</u>

Explanation:

The question is not completely clear because some missing parts or grammar (syntax) errors.

Interpreting it, the question is <em>what is the Kelvin temperatue of the air in a tire, when the pressure in the tire has increased to 225 kPa, if the initial conditions of the air inside the tire were 188kPa of pressure and a temperature of 32ºC.</em>

To solve this, you can assume constant volume and use the law of Gay-Lussac for ideal gases:

$\dfrac{P_1}{T_{1}}=\dfrac{P_2}{T_2}$

That equation works with absolute temperatures, i.e. Kelvin.

32ºC = 32 + 273.15 K = 305.15K

Then solve for T₂, substitute and compute:

$T_2=P_2\times \dfrac{T_1}{P_{1}}=225kPa\times \dfrac{305.15K}{188kPa}$

$T_2=413.90K\approx 414K\longleftarrow answer$

8 0

3 years ago