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mart [117]
3 years ago
12

Please help! 10 points

Chemistry
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

<u>1 mole of Fe and 1.5 moles of CO2</u>

Explanation:

<u>Fe2O3 + CO → Fe + CO2</u>

This is a trick question.  The equation is not balanced properly.  To start, note that one molecule of Fe2O3 contain 2 Fe atoms, while there is only 1 Fe atom on the product side.  And the oxygens are also missing (from 4 to 2).  We cannot use this equation, as written.

Here's one that is balanced:

<h2><u>Fe2CO3 + 3CO = 2Fe + 3CO2</u></h2>

<u>I'll use this one to answer the question.</u>

1.  <u>If 3 moles of Fe2O3 react with 1.5 moles of CO, how many moles of each product are formed?</u>

The balanced equation tells us that 1 mole of Fe2O3  will react with 3 moles CO to produce 2 moles of Fe and 3 moles of CO2.  <u><em>If we had enough CO</em></u>,  3 moles Fe2O3 will produce 6 moles of Fe and 9 moles of CO2.  But note that we'd also need 9 moles of CO for a complete reaction.  We only have 1.5 moles, probably due to Stanley, our new manager.  So we're limited by the CO, and we'll have to delete our first analysis and work from 1.5 moles of CO.

<h2>If we have 1.5 moles CO, we'll produce:</h2><h2> <u>1 mole of Fe and 1.5 moles CO2.</u></h2>
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1)The average lethal dose of Valium is 1.52 mg/kg of body weight. Estimate how many grams of Valium would be lethal for a 200.-l
oksano4ka [1.4K]

Answer:

1. 0.138g of valium would be lethel in the woman

2. 125mg/min is the drip of the patient

Explanation:

1. In a body, an amount of Valium > 1.52mg / kg of body weight would be lethal.

A person that weighs 200lb requires:

200<u>lb</u> × (453.6<u>g</u> / <u>1lb</u>) × (1kg / 1000<u>g</u>) = <em>90.72kg (Weight of the woman in kg)</em>

90.72kg × (1.52mg / kg) =

137.9mg ≡

<h3>0.138g of valium would be lethel in the woman</h3>

2. The IV contains 1.5g = 1500mg/mL.

If the patient is receiving 5.0mL/h, its rate in mg/h is:

5.0<u>mL</u>/h × (1500mg/<u>mL</u>) = 7500mg/h

Now as 1h = 60min:

7500mg/<u>h</u> × (1<u>h</u> / 60min) =

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using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius​
lukranit [14]

Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

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Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

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If an organism has two identical alleles for a trait, (example TT or tt), it is said to be<br>​
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