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Masja [62]
3 years ago
6

The diagram shows the back fences of three houses in a small neighborhood. The lengths of the fences are given.

Mathematics
2 answers:
Verizon [17]3 years ago
8 0

Answer:

B. They are a Pythagorean triple that forms a right triangle.

Step-by-step explanation:

Edge 2021 :)

Kazeer [188]3 years ago
5 0

Answer:

They are a Pythagorean triple that forms a right triangle

Step-by-step explanation:

took the test

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A bag has 2 blue marbles 3 red marbles and 5 white marbles. Which event has a probability greater than 1/5 select three options
Evgesh-ka [11]

Answer:

all

Step-by-step explanation:

all of them has the probability

4 0
3 years ago
The Barnes family has a coupon for 10% off their dinner. If their bill comes to $82.50 and they wish to tip 15%, what will they
satela [25.4K]

Answer:

Total cost= $86.25

Step-by-step explanation:

Giving the following information:

Discount= 10%

Nill= $82.5

Tip= 15%

<u>First, we need to calculate the discounted price:</u>

Discount price= 82.5 / 1.1= $75

<u>Now, the tip:</u>

Tip= 75*0.15= $11.25

<u>Finally, the total cost:</u>

Total cost= 75 + 11.25

Total cost= $86.25

3 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Find the length of side BC.<br> Give your answer to 1 decimal place.
Alenkasestr [34]

Use

Angle sin A = AB/BC

AND FIND IT OUT

PLEASE FOLLOW ME

5 0
3 years ago
Read 2 more answers
A.What is the slope
zhuklara [117]

Answer:

A. 1

B. -1

C. Proportional

D. y=x-1

7 0
2 years ago
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