I NEED HELP PLEASE I need to find the slope

Four points partition the directed line segment from A to B. • Point P partitions the directed line segment from A to B into a 3

Alecsey [184]

Answer:

S is closest to B.

Step-by-step explanation:

Given a directed line segment from point A to B.

Point P divides the line A to B in a ratio 3:4.

Point Q divides the line A to B in a ratio 4:3.

Point R divides the line A to B in a ratio 2:5.

Point S divides the line A to B in a ratio 5:2.

To find:

The point which is closest to the point B.

Solution:

Here, to find the point closest to B we need to find the distances PB, QB, RB and SB.

We can see the sum of ratio 3:4, 4:3, 2:5 and 5:2 is 7.

Let the distance between A and B be 7 units.

Now, the distances can be found easily.

$PB = \dfrac{4}{7}\times 7 = 4\ units$

$QB = \dfrac{3}{7}\times 7 = 3\ units$

$RB = \dfrac{5}{7}\times 7 = 5\ units$

$SB = \dfrac{2}{7}\times 7 = 2\ units$

The point which has the minimum distance from point B, will be nearest to B.

We can clearly observe that SB is the minimum distance.

Therefore, S is closest to B.

4 0

3 years ago

Read 2 more answers

A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.

zzz [600]

Answer:

$CI=(66.54,78.46)$

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , $\bar{X}=72.5\%$ , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

$\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}$

From the t-table with 9 degree of freedom for $\frac{\alpha}{2}=0.005$

$t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}$

$t_{n-1,\frac{\alpha}{2}}=3.250$

The 99% confidence interval is given by,

$CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}$

$CI=72.5 \pm 5.96$

$CI=(72.5+5.96),(72.5-5.96)$

$CI=(66.54,78.46)$

8 0

3 years ago

Which function has the same graph as x + y = 112 OA x) = -y + 11 OB. f(x) = -x + 11 Oc. x) = x- 11 O D. x) = y-11

Lera25 [3.4K]

Answer:

B. f(x) = -x + 11

Step-by-step explanation:

First if you rearrange the equation you get f(x) = -x + 11, like this:

x + y = 11

Minus x from both sides

y = -x + 11

F(x) and y are interchangeable so we just put f(x) in

f(x) = -x + 11

Each of the graphs are attached and we see that they are the same!

Hope this helps!!

- Kay

4 0

3 years ago

How would I do this?

Lelu [443]

I'm not sure about part B, but part A will have the answer "if Ron eats lunch today, then he will drink a glass of milk" (without quotes of course)

The idea is that we have these arguments in symbolic form
P = Ron eats lunch today
Q = Ron eats a sandwich
R = Ron will drink a glass of milk

The format is
"If P then Q" ----> "if Q then R" so therefore "If P then R"

We see that P leads to Q, then Q leads to R. So overall P leads to R. We connect them as a chain of sorts. We can skip over Q since we know the first point will lead to the last. Think of it as a shortcut of sorts.

8 0

3 years ago

Find the vertex of the graph of the function.

lapo4ka [179]

Answer: The correct options are (1) (5,10), (2) (3,-3), (3) x = -1, (4) $y=(x+2)^2+3$ , (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

$f(x)=a(x-h)^2+k$ .....(1)

Where, (h,k) is the vertex of the parabola.

(1)

The given equation is,

$f(x)=(x-5)^2+10$

Comparing this equation with equation (1),we get,

$h=5$ and $k=10$

Therefore, the vertex of the graph is (5,10) and the fourth option is correct.

(2)

The given equation is,

$f(x)=3x^2-18x+24$

$f(x)=3(x^2-6x)+24$

To make perfect square add $(\frac{b}{2a})^2$ , i.e., $9$ . Since there is factor 3 outside the parentheses, so subtract three times of 9.

$f(x)=3(x^2-6x+9)+24-3\times 9$

$f(x)=3(x-3)^2-3$

Comparing this equation with equation (1),we get,

$h=3$ and $k=-3$

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

(3)

The given equation is

$f(x)=4x^2+8x+7$

$f(x)=4(x^2+2x)+7$

To make perfect square add $(\frac{b}{2a})^2$ , i.e., $1$ . Since there is factor 4 outside the parentheses, so subtract three times of 1.

$f(x)=4(x^2+2x+1)+7-4$

$f(x)=4(x+1)^2+3$

Comparing this equation with equation (1),we get,

$h=-1$ and $k=3$

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

$y=x^2+4x+7$

To make perfect square add $(\frac{b}{2a})^2$ , i.e., $2^2$ .

$f(x)=x^2+4x+4+7-4$

$f(x)=(x+2)^2+3$

Therefore, the correct option is 4.

(5)

The given equation is,

$h=-16t^2+672t$

It can be written as,

$h=-16(t^2-42t)$

It is a downward parabola. so the maximum height of the function is on its vertex.

The x coordinate of the vertex is,

$x=\frac{b}{2a}$

$x=\frac{42}{2}$

$x=21$

Therefore, after 21 seconds the projectile reach its maximum height and the correct option is first.

(6)

The given equation is,

$f(x)=3x^3-12x^2-15x$

$f(x)=3x(x^2-4x-5)$

Use factoring method to find the factors of the equation.

$f(x)=3x(x^2-5x+x-5)$

$f(x)=3x(x(x-5)+1(x-5))$

$f(x)=3x(x-5)(x+1)$

Equate each factor equal to 0.

$x=0,-1,5$

Therefore, the zeros of the given equation is 0, -1, 5 and the correct option is 2.

3 0

3 years ago

I NEED HELPPLEASE I need to find the slope ​

I NEED HELPPLEASE I need to find the slope