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Radda [10]
2 years ago
14

I NEED HELPPLEASE I need to find the slope ​

Mathematics
1 answer:
Mumz [18]2 years ago
4 0
The slope is 3 over 5 or 3/5
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The weight of tigers follow a normal distribution with a mean of 220 kg and a SD of 30 kg. 1) If we randomly select a tiger, wha
mylen [45]

Answer:

0.89736

Step-by-step explanation:

We solve this question using z score formula

Z score = x - μ/σ

x = raw score

μ = population mean

σ = population standard deviation

Hence,

x = 258, μ = 220, σ = 30

Z = 258 - 220/30

=1.26667

Probability value from Z-Table:

P(x<258) = 0.89736

Therefore, the probability that his weights is less than 258 kg is 0.89736

6 0
3 years ago
What your expect to gen.math subject​
sveta [45]
Can you elaborate on ur question
6 0
3 years ago
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Can a line segment have two midpoints ?
zzz [600]
Actually, no they cannot. The midpoint is the single point at the very center of the line segment. Since no segment can have multiple centers, they cannot have more than a single midpoint. Sorry :3

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5 0
3 years ago
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The output with the y being -4
aivan3 [116]

For this case we have a function of the form y = f (x), where f (x) = - 4x. We must find the values of "and" according to the following function:y = -4x

So:

f (-6) = - 4 (-6) = 24\\f (-2) = - 4 (-2) = 8\\f (3) = - 4 (3) = - 12

Thus, the values are:

24,8, -12

Answer:

24,8, -12

3 0
3 years ago
Direct variation or not a direct variation<br><br> y=5/x
MrRissso [65]

Answer:

not direct variation

Step-by-step explanation:

The equation for x and y in direct variation is

y = kx ← k is the constant of variation

y = \frac{5}{x} is not in this form, thus not direct variation.

The equation for x and y varying inversely is

y = \frac{k}{x} ← k is the constant of variation

y = \frac{5}{x} is in this form and represents inverse variation

7 0
3 years ago
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