Solve 5^5x=(125)^x+2

Find the cost per ounce of a gold alloy made from 30 oz of pure gold that costs $1290 per ounce and 60 oz of an alloy that costs

Romashka [77]

The answer would be $24.55 per oz of gold alloy so rounded up would be $25

6 0

3 years ago

Read 2 more answers

Shaneya purchased a membership to play basketball at her local gym. The membership costs $450 for the year, plus she pays $10 to

olga55 [171]

Answer:

55

Step-by-step explanation:

So start with the total 1,000

then take the 1,000 and minus it by the 450 year so then you can see how much money you have left for the times that she can go to the gym to play.

1,000 - 450 = 550

Now you 550 dollars because basic math. Then you divide the number you got which the number you got was 550 so 550÷10 you divide it by 10 because the rent is 10 each time.

550 ÷ 10 = <u>55</u>

Now you get 55 so that means she can got to the gym 55 times before she goes over 1,000 dollars!

Hoped this helped. Don't forget a middle school person did this so I bet you could have too!

6 0

3 years ago

Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

3 years ago

Is the statement 2(3+5x)=6+5x always true?

mihalych1998 [28]

No that statement is not always true. There is only one solution to this equation.

5 0

3 years ago

Read 2 more answers

Sal bought 2 shirts and a hat. Sal remembers each shirt was $10, and the total was $50. Which equation helps answer the question

Oksana_A [137]

Answer: the hat= $30. The equation you would use to solve is 2s+h=50

Step-by-step explanation:

2s+h=50

2(10)+h=50

20+h=50

-20. -20

h=30

3 0

3 years ago