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Anastaziya [24]
3 years ago
11

A circular wire loop lies inside a region of space containing a magnetic field. The direction of the magnetic field is out of th

e screen and parallel to the central axis of the loop. The magnitude of the magnetic field increases as a function of time. A circular loop oriented parallel to the plane of the screen lies inside a region containing magnetic field B. The field is directed out of the screen and is increasing. What is the direction of the induced current in the loop
Physics
1 answer:
jekas [21]3 years ago
6 0

Answer:

clockwise

Explanation:

According to the law given by Lenz, known as the Lenz law, it is said that a current induced in the circuit which is due to the change in the magnetic field and is so directed so as to oppose the change in the flux and to apply a force in the opposite direction if the force.

Here, as the magnetic field is directed out of the screen, the current flows in the direction which is clockwise in the loop and it opposes the increasing magnetic field.

The clockwise induced current will produce magnetic field in to the screen.

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Answer:

9.4 x 10⁴ m/s

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v₂ = 9.42 x 10⁴ m/s.

= 9.4 x 10⁴ m/s

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A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 3
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Since the acceleration is uniform, we can calculate it from the data we are given:

a = (vf - vi)/2

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Then use Suvat's equation:

x(t) = vi*t + 0.5 * a * t

where t=20s

3 0
4 years ago
Planck's constant, h, is 6.626 x 10-34 js. the speed of light in a vacuum, c, is 3.00 x 108 m/s. calculate the frequency of a gr
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4 0
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How much do you know about the water cycle and the impact that humans have on the water cycle?
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7 0
3 years ago
A charge of +1 coulomb is place at the 0 cm mark of a meter stick. A charge of +4 coulombs is placed at the 100 cm mark of the s
UkoKoshka [18]

As per the question the charge of one coulomb is at 0 cm of the metre stick.the second charge of 4 coulomb is situated at at 100 cm of metre stick.

hence the separation distance between them is 100 cm.

now as per the question a proton is set up  between them in such a way that the net force on it is zero

let the charge of proton is q coulomb let the proton is situated at distance of x cm from the charge 1 coulomb.hence it is situated at a distance of 100-x cm from the charge 4 coulomb.

the force exerted by 1 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}

the force exerted by 4 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{q*4}{[100-x]^2}

as the net force is zero,hence-

\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}=\frac{1}{4\pi\epsilon} \frac{4*q}{[100-x]^2}

=\frac{1}{x^2} =\frac{4}{[100-x]^2}


x^2=\frac{[100-x[^2}{4}[/tex[tex]x=\frac{100-x}{2}

3x=100

x=\frac{100}{3}

=33.33333cm   [ans]







4 0
3 years ago
Read 2 more answers
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