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dedylja [7]
3 years ago
12

An unknown element, X, is a nonmetal that contains seven valence electrons. Element X most likely forms ___________ covalent bon

ds.
A) 1
B) 2
C) 3
D) 4
Chemistry
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

1

Explanation:

An unknown element, X, is a nonmetal that contains seven valence electrons. Element X most likely forms <u>1 </u>covalent bond.

Nonmetals gain the electron to complete the octet and form anion. Consider the example of halogen.

When it combine with another halogen atom they form covalent bond. There are seven valance electrons in outer most orbital of halogen atom. By combining with other halogen atom they form one covalent bond and complete the octet.

For example:

Cl atom combine with other Cl atom and form Cl₂.

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How many electrons does an aluminum ion have with a +3
Varvara68 [4.7K]

Answer:10

Explanation:

3 0
3 years ago
2HgO—&gt;2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?
jok3333 [9.3K]

Answer:

Theoretical yield = 3.52 g

Percent yield =65.34%

Explanation:

Given data:

Mass of HgO = 46.8 g

Theoretical yield of O₂ = ?

Percent yield of O₂ = ?

Actual yield of O₂ =  2.30 g

Solution:

Chemical equation:

2HgO  →   2Hg + O₂

Number of moles of HgO = mass/ molar mass

Number of moles of HgO = 46.8 g / 216.6 g/mol

Number of moles of HgO = 0.22 mol

Now we will compare the moles of HgO with oxygen.

                         HgO             :             O₂

                             2               :               1

                            0.22           :          1/2×0.22 = 0.11 mol

Theoretical yield:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  0.11 mol × 32 g/mol

Mass of oxygen = 3.52 g

Percent yield :

Percent yield = actual yield / theoretical yield × 100

Percent yield = 2.30 g/ 3.52 g × 100

Percent yield =65.34%

5 0
3 years ago
The atomic number of silicon (Si) is 14. What's the electron configuration for silicon? Question 1 options:
Tom [10]

Answer:

[Ne] 3S2 3P2

Explanation:

Good evening

8 0
3 years ago
When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
Not sure if my answers are even correct. i am so confused
Mamont248 [21]

Answer:

#3 is the percentage for sodium i believe and 4 is right

Explanation:

7 0
3 years ago
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