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Rom4ik [11]
3 years ago
11

1.

Engineering
1 answer:
garik1379 [7]3 years ago
5 0

Answer:

The answer is below

Explanation:

1)

R_{AB}=(500+500)||(500+500)\\\\R_{AB}=1000||1000\\\\R_{AB}=\frac{1000*1000}{1000+1000} \\\\R_{AB}=500\ \Omega

2)

R_{AB}=1000\|(1000+1000+1000)\\\\R_{AB}=1000||3000\\\\R_{AB}=\frac{1000*3000}{1000+3000} \\\\R_{AB}=750\ \Omega

3)

Because of the short, the resistance is zero.

R_{AB}=0

4)

R_{AB}=940\ \Omega

5)

R_{AB}=2200||2200||(2200+2200)\\\\R_{AB}=2200||2200||4400\\\\\frac{1}{R_{AB}}=\frac{1}{2200}  +\frac{1}{2200}  +\frac{1}{4400}  \\\\\frac{1}{R_{AB}}=\frac{5}{4400}\\\\R_{AB}=880

6)

R_{AB}=(220+100)||470||330\\\\R_{AB}=320||470||330\\\\\frac{1}{R_{AB}}=\frac{1}{320}  +\frac{1}{470} +\frac{1}{330} \\\\R_{AB}=120.7\ \Omega

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iVinArrow [24]

Answer:

  • The resistance of the circuit is 1250 ohms
  • The inductance of the circuit is 0.063 mH.

Explanation:

Given;

current at resonance, I = 0.2 mA

applied voltage, V = 250 mV

resonance frequency, f₀ = 100 kHz

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At resonance, capacitive reactance (X_c) is equal to inductive reactance (X_l),

Z = \sqrt{R^2 + (X_ l - X_c)^2} \\\\But \ X_l= X_c\\\\Z = R

Where;

R is the resistance of the circuit, calculated as;

R = \frac{V}{I} \\\\R = \frac{250 \ \times \ 10^{-3}}{0.2 \ \times \ 10^{-3}} \\\\R = 1250 \ ohms

The inductive reactance is calculated as;

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The inductance is calculated as;

X_l = \omega L = 2\pi f_o L\\\\L = \frac{X_l}{2\pi f_o}\\\\L = \frac{39.789}{2\pi (100 \times 10^3)}  \\\\L= 6.3 \ \times \ 10^{-5} \ H\\\\L = 0.063 \times \ 10^{-3} \ H\\\\L = 0.063 \ mH

5 0
3 years ago
A long corridor has a single light bulb and two doors with light switch at each door.
Zigmanuir [339]

Answer:

The answer is below

Explanation:

Let A represent the first switch, B represent the second switch and C represent the bulb. Also, let 0 mean  turned off and 1 mean turned on. Since when both switches are  in the same position, the light is off. This can be represented by the following truth table:

A                    B                       C (output)

0                    0                        0

0                    1                          1

1                     0                         1

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The logic circuit can be represented by:

C = A'B + AB'

The output (bulb) is on if the switches are at different positions; if the switches are at the same position, the output (bulb) is off. This is an XOR gate. The gate is represented in the diagram attached below.

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An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions. If the
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Answer:C  0.12 V

Explanation:

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