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Rom4ik [11]
3 years ago
11

1.

Engineering
1 answer:
garik1379 [7]3 years ago
5 0

Answer:

The answer is below

Explanation:

1)

R_{AB}=(500+500)||(500+500)\\\\R_{AB}=1000||1000\\\\R_{AB}=\frac{1000*1000}{1000+1000} \\\\R_{AB}=500\ \Omega

2)

R_{AB}=1000\|(1000+1000+1000)\\\\R_{AB}=1000||3000\\\\R_{AB}=\frac{1000*3000}{1000+3000} \\\\R_{AB}=750\ \Omega

3)

Because of the short, the resistance is zero.

R_{AB}=0

4)

R_{AB}=940\ \Omega

5)

R_{AB}=2200||2200||(2200+2200)\\\\R_{AB}=2200||2200||4400\\\\\frac{1}{R_{AB}}=\frac{1}{2200}  +\frac{1}{2200}  +\frac{1}{4400}  \\\\\frac{1}{R_{AB}}=\frac{5}{4400}\\\\R_{AB}=880

6)

R_{AB}=(220+100)||470||330\\\\R_{AB}=320||470||330\\\\\frac{1}{R_{AB}}=\frac{1}{320}  +\frac{1}{470} +\frac{1}{330} \\\\R_{AB}=120.7\ \Omega

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Svetllana [295]

Answer:

This question assesses how well an engineer can explain complicated designs to people who work in other industries. It's important that your mechanical engineer be able to articulate their idea to marketing and executive teams in your company before production begins.

What to look for in an answer:

Evidence they can communicate complicated designs to other teams in a way that makes sense

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Understanding of the importance of communicating engineering points to others

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3 0
4 years ago
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A parallel circuit with two branches and an 18 volt battery. Resistor #1 on the first branch has a value of 220 ohms and resisto
likoan [24]

Answer:

  2.455 W

Explanation:

The power dissipated in each branch is ...

  P = V^2/R

So, the branch powers are ...

  branch 1: 18^2/220 ≈ 1.473 W

  branch 2: 18^2/330 ≈ 0.982 W

Total power is ...

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8 0
3 years ago
A fuel gas containing 45.00 mole% methane and the balance ethane is burned completely with pure oxygen at 25.00 degree C, and th
Dennis_Churaev [7]

Answer:

A)

- Q ( kw ) for vapor =  -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B )

- Q ( kj ) for vapor  = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

Explanation:

Given data :

45.00 % mole of methane

55.00 % of ethane

attached below is a detailed solution

A) calculate - Q(kw)

- Q ( kw ) for vapor =  -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B ) calculate  - Q ( KJ )

- Q ( kj ) for vapor  = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

since combustion takes place in a constant-volume batch reactor

7 0
3 years ago
A tension member must be designed for a service dead load of 18 kips and a service live load of 2 kips.
ella [17]

Answer:

A) max factored load ( pv = 1.4 * 18 ) = 25.2 kips

B) max load factored load  = ( Pa = 18 + 2 ) = 20 kips

Explanation:

service dead load = 18 kips

service live load = 2 kips

A) Determine the maximum factored load and controlling AISC load combination

max factored load ( pv = 1.4 * 18 ) = 25.2 kips

DL = 18 kips

LL = 2 kips

B) Determine the max load and controlling AISC load combination

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attached below

4 0
3 years ago
Please help asap! I will give brainlist!
dexar [7]

Answer:

i did this this is b

Explanation:

7 0
3 years ago
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